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Gennadij [26K]
3 years ago
5

Manganese, Mn, forms two ions, one with a 2+ charge and one with a 3+ charge. What is the formula for manganese (II) sulfide?

Chemistry
1 answer:
maria [59]3 years ago
4 0
It would be MnSO4

The (II) lets you know it’s the form with a 2+ charge and Sulfate has a 2- charge

These will cancel out making it plain MnSO4

If it was manganese (iii) sulfide the answer would be Mn2(SO4)3
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How are the functions of a flower's stamen and pistil related to reproduction?
Alina [70]

Answer: the essential parts of a flower

Explanation:

are engaged with seed creation. In the event that a blossom contains both useful stamens and pistils, it is known as an ideal bloom, regardless of whether it doesn't contain petals and sepals. On the off chance that either stamens or pistils are deficient with regards to, the blossom is called imperfect.

6 0
3 years ago
A person's blood type is determined by the presence and absence of specific antigens on the cell membrane. Which of these would
sukhopar [10]

Answer:

C - no antibodies

Explanation:

I dont think there is any blood type without antibodies

5 0
3 years ago
Cis-3-tert-Butylcyclohexanol has the tert-butyl group in the equatorial position and the alcohol in the ________ position.
Anni [7]

Answer:

Axial

Explanation:

In the most stable conformation of Cis-3-tert-Butylcyclohexanol, the tert-butyl group is at equatorial position and the alcohol group is in the axial position.

If the tert-butyl group is placed in equatorial position, repulsions are minimized. The bulkier the group, the greater the energy difference between the axial and equatorial conformers. Hence for a ring having a bulky substituent, such bulky substituent is better placed in the equatorial position.

The energy difference between the conformers of Cis-3-tert-Butylcyclohexanol is so high that the compound is almost "frozen" in a conformation  where the tert-butyl groups are equatorial and the -OH groups are axial. This conformer is more stable by 24 KJ/mol.

8 0
3 years ago
If 42.9 mL of rubbing alcohol is
lisov135 [29]

Answer:

19.8 %

Explanation:

V% = ( V of solute \ 100 ml  of solution ) ×100%  =

   the volume of the solute in 100ml solition = 20 ml

  42.9 ml of solute ----------215 ml solution

     ×                     -----------  100 ml solution

42.6 ×   100 ml  ÷ 215 ml

= 19.8 ml of solute

the V% =   (19.8 ÷ 100)  ×100% = 19.8%

3 0
4 years ago
The weak base ionization<br> constant (Kb) for HCO3 is<br> equal to:
hammer [34]

Weak bases are alkaline solution that does not get completely dissociated. The dissociation constant will be the ratio of the concentration of the products to the reactants.

<h3>What is a weak base ionization constant?</h3>

The weak base ionization constant is the equilibrium constant that is given as the division of the products of the ionization to the concentration of the reactants.

The reaction for HCO₃ is given as:

HCO₃⁻ + OH⁻ ⇄ CO₃²⁻ + H₂O

The value of Ka for the given reaction will be:

Ka = [CO₃²⁻][H₂O] ÷ [HCO₃⁻ ][OH⁻]

Therefore, the Ka of the weak carbonic acid is given as the ratio of the concentration of the products to the reactants.

Learn more about the weak ionization constant here:

brainly.com/question/27200344

#SPJ1

8 0
2 years ago
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