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Tema [17]
3 years ago
5

Which title is most appropriate for this table?

Chemistry
2 answers:
shutvik [7]3 years ago
5 0

Answer : The correct option is, (A) uses of functional groups involving oxygen.

Explanation :

(1) R-OH : It belongs to an alcoholic functional group in which the the -OH group is directly attached to the alkyl group of carbon.

(2) R-O-R^' : It belongs to an ether functional group in which the the oxygen is directly attached to the two alkyl group of carbon.

(3) R-CO-R^' : It belongs to ketone functional group in which the the -CO group is directly attached to the two alkyl group of carbon.

(4) R-CHO : It belongs to an aldehyde functional group in which the the -CHO group is directly attached to the alkyl group of carbon.

(5) R-COOH : It belongs to carboxylic acid functional group in which the the -COOH group is directly attached to the alkyl group of carbon.

(6) R-COO-R^' : It belongs to ester functional group in which the the -COO group is directly attached to the two alkyl group of carbon.

R-NH_2 : It belongs to an amine functional group in which the the -NH_2 group is directly attached to the alkyl group of carbon.

R-X : It belongs to halide functional group in which the the -X group (all the halogens) is directly attached to the alkyl group of carbon.

From the above and from the question we conclude that, some uses of functional groups are given in which the an oxygen are present in all the functional groups.

Hence, the correct option is, (A) uses of functional groups involving oxygen.

Anastasy [175]3 years ago
4 0

a.uses of functional groups involving oxygen

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Calculate the mass of 120cc of nitrogen at stp .how many numbers of molecules are prrsent
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Answer:

3.2 x 10²¹molecules

Explanation:

Given parameters:

Volume of nitrogen gas = 120cm³

Unknown:

Mass of nitrogen gas = ?

Number of molecules  = ?

Solution:

To solve this problem, note that;

   1 mole of gas occupies a volume of 22.4L at STP

  Now;

   convert 120cm³ to L ;

           1000cm³  = 1L

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    Since;

            22.4L of gas has 1 mole at STP

            0.12L of gas will have \frac{0.12}{22.4}   = 0.0054mole at STP

So;

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    Mass of N₂  = 0.0054 x 28  = 0.15g

Now;

        1 mole of a gas will have 6.02  x  10²³ molecules

      0.0054 mole of N₂ will contain   0.0054 x  6.02  x  10²³ =

                          3.2 x 10²¹molecules

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