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Tema [17]
3 years ago
5

Which title is most appropriate for this table?

Chemistry
2 answers:
shutvik [7]3 years ago
5 0

Answer : The correct option is, (A) uses of functional groups involving oxygen.

Explanation :

(1) R-OH : It belongs to an alcoholic functional group in which the the -OH group is directly attached to the alkyl group of carbon.

(2) R-O-R^' : It belongs to an ether functional group in which the the oxygen is directly attached to the two alkyl group of carbon.

(3) R-CO-R^' : It belongs to ketone functional group in which the the -CO group is directly attached to the two alkyl group of carbon.

(4) R-CHO : It belongs to an aldehyde functional group in which the the -CHO group is directly attached to the alkyl group of carbon.

(5) R-COOH : It belongs to carboxylic acid functional group in which the the -COOH group is directly attached to the alkyl group of carbon.

(6) R-COO-R^' : It belongs to ester functional group in which the the -COO group is directly attached to the two alkyl group of carbon.

R-NH_2 : It belongs to an amine functional group in which the the -NH_2 group is directly attached to the alkyl group of carbon.

R-X : It belongs to halide functional group in which the the -X group (all the halogens) is directly attached to the alkyl group of carbon.

From the above and from the question we conclude that, some uses of functional groups are given in which the an oxygen are present in all the functional groups.

Hence, the correct option is, (A) uses of functional groups involving oxygen.

Anastasy [175]3 years ago
4 0

a.uses of functional groups involving oxygen

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If 30 grams of KCl is dissolved at 10°C, how many additional grams would be needed to make the solution saturated at 60°C? * Cap
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If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.

<h3>What is a saturated solution?</h3>

A saturated solution is a solution in which there is so much solute that if there was any more, it would not dissolve. Its concentration is the same as the solubility at that temperature.

  • Step 1. Calculate the mass of water.

At 10 °C, the solubility is 31.2 g KCl/100 g H₂O.

30 g KCl × 100 g H₂O/31.2 g KCl = 96 g H₂O

  • Step 2. Calculate the mass of KCl required to prepare a saturated solution at 60 °C.

At 60 °C, the solubility is 45.8 g KCl/100 g H₂O.

96 g H₂O × 45.8 g KCl/100 g H₂O = 44 g KCl

  • Step 3. Calculate the mass of KCl that must be added.

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If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.

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