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vovangra [49]
3 years ago
7

Sodium nitrate and lead (ii) acetate express your answer as a chemical equation. identify all of the phases in your answer. ente

r noreaction if no no reaction occurs.
Chemistry
2 answers:
ira [324]3 years ago
8 0

Sodium nitrate reacts with lead acetate to form sodium acetate and lead nitrate. The chemical equation can be represented as:

2NaNO3(aq) + Pb(CH3COO)2(aq) → Pb(NO3)2(aq) + 2CH3COONa(aq)

Sodium nitrate = aqueous phase

Lead acetate= aqueous phase

Lead nitrate = aqueous phase

Sodium acetate = aqueous phase

ICE Princess25 [194]3 years ago
3 0

Answer: 2NaNO_3(aq)+(CH_3COO)_2Pb(aq)\rightarrow 2CH_3COONa(aq)+Pb(NO_3)_2(aq)

Explanation: A double displacement reaction is one in which exchange of ions take place.

The compounds which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Thus the exchange of ions take place and all the compounds are soluble so the chemical formulas are followed by the symbol (aq).

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Explanation: When solutions of potassium iodide and lead nitrate are combined?

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3 years ago
1. Which of the following is a correctly written thermochemical equation?
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calculate how much acid (acetic acid) and how much conjugate base (sodium acetate) must be used to make 500ml of a 0.8m acetate
kirza4 [7]

For the desired pH of 5.76, 0.365 mol of acetate and 0.035 mol of acid are to be added

let the concentration of acetate be x

then the concentration of acid will be (0.8 - x)

pKa of acetate buffer = 4.76

pH = pKa + log([acetate]/[acid])

⇒4.76 = 4.76 + log(x/(0.8-x))

⇒log(x/(0.8-x)) = 0

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number of mol acid = 0.4*0.5

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number of mol acetate to be added = 0.73*0.5 = 0.365 mol

number of mol acid to be added = 0.07*0.5 = 0.035 mol

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