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Likurg_2 [28]
3 years ago
10

A wave has a velocity of 24 m/s and a period of 3.0 s. Calculate the wavelength of the wave.

Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Velocity (unit:m/s) of the wave is given with the formula:

v=f∧,

where f is the frequency which tells us how many waves are passing a point per second (unit: Hz) and ∧ is the wavelength, which tells us the length of those waves in metres (unit:m)

f=1/T , where T is the period of the wave.

In our case: f=1/3

∧=v/f=24m/s/1/3=24*3=72m

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Why does a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s?
andrew11 [14]

A dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.

s = vt - 1 / 2 at²

s = Displacement

v = Final velocity

t = Time

a = Acceleration

s = 5 m

t = 1 s

a = 10 m / s²

5 = ( v * 1 ) - ( 1 / 2 * 10 * 1 * 1 )

5 = v - 5

v = 10 m / s

The equation used to solve the given problem is an equation of motion. In a free fall motion, usually air resistance is not considered for easier calculation. If air resistance is considered acceleration cannot be constant throughout the entire motion.

Therefore, a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.

To know more about equation of motion

brainly.com/question/5955789

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4 0
1 year ago
Using the definition of moment of inertia, calculate icm, the moment of inertia about the center of mass, for this object.
Step2247 [10]
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<span>1. Icm (at point A) = 2mr^2 
hope this helps</span>
3 0
3 years ago
What do you need to make 100 minutes charges neutral
Maru [420]
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4 0
3 years ago
A centrifuge in a medical laboratory rotates at an angular speed of 3,500 rev/min, clockwise (when viewed from above). When swit
Ratling [72]

Answer:

The magnitude of angular acceleration is 232.38\ rad/s^2.

Explanation:

Given that,

Initial angular velocity, \omega_i=3500\ rev/min=366.5\ rad/s

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Number of revolution, \theta=46=289.02\ rad

We need to find the magnitude of angular acceleration. It can be calculated using third equation of rotational kinematics as :

\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{-(366.51)^2}{2\times 289.02}\\\\\alpha =-232.38\ rad/s^2  

So, the magnitude of angular acceleration is 232.38\ rad/s^2. Hence, this is the required solution.

6 0
3 years ago
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Radda [10]
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