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Furkat [3]
3 years ago
6

You have two pieces of wire that allow electrons to pass through them when they are connected to each other. if you insert a met

al cable between the wires, electrons still flow easily the metal cable is ?
A. a circuit
B. an insulator
C. a fuse
D. a conductor
Physics
1 answer:
Andre45 [30]3 years ago
5 0
A. I think that's it.
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Write any two difference between CGS and MKS system of measurement ?​
Tresset [83]

Answer:

MKS stands for Meter, Kilogram and second. In this system of unit mass is given in Kilogram, length in meter and time in second. ... CGS system stands for Centimeter- Gram- Second system. In CGS system, length is measured in centimeters mass is measured in grams and time is in seconds.

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The gas waste generated by many power plants is
lapo4ka [179]

carbon dioxide

is the answer

5 0
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A ball with mass 0.11 kg is thrown upward with initial velocity 10 m/s from the roof of a building 20 m high. Neglect air resist
inessss [21]

Answer:

a) H=25.1020\ m

b)  t=3.2838\ s

Explanation:

Given:

  • mass of the ball thrown up, m=0.11\ kg
  • initial velocity of the ball thrown up, u=10\ m.s^{-1}
  • height above the ground from where the ball is thrown up, h=20\ m

a)

Maximum height attained by the ball above the roof level can be given by the equation of motion.

As,

v^2=u^2-2g.h'

where:

v= final velocity at the top height of the upward motion =0\ m.s^{-1}

g= acceleration due to gravity

h'= height of the ball above the roof

Now,

0^2=10^2-2\times 9.8\times h'

h'=5.10\ m

Therefore total height above the ground:

H=h+h'

H=20+5.1020

H=25.1020\ m

b)

Now we find the time taken in raching the height h':

v=u-gt'

v= final velocity at the top of the motion =0\ m.s^{-1}

So,

0=10-9.8\times t'

t'=1.0204\ s

Now the time taken in coming down to the ground from the top height:

H=u'.t_d+\frac{1}{2} g.t_d^2

where:

u'= is the initial velocity of the ball in course of coming down to ground from the top =0\ m.s^{-1}

Here the direction acceleration due to gravity is same as that of motion so we are taking them positively.

25.1020=0+0.5\times 9.8\times t_d^2

t_d=2.2634\ s

Therefore the total time taken in by the ball to hit the ground after it begins its motion:

t=t'+t_d

t=1.0204+2.2634

t=3.2838\ s

4 0
3 years ago
A mole of gas at 0.0oC and 760. torr occupies 22.4 L. What is the volume of this gas at 25.oC and 760. torr
daser333 [38]

Answer:

Explanation:

Given

Temperature of gas at First stage T_1=0^{\circ}C\approx 273\ K

Pressure of gas at First stage P_1=760\ torr

Volume Occupies V_1=22.4\ L

If the Pressure and Temperature at second stage is

P_2=760\ torr

T_2=25^{\circ}C\approx 298\ K

Using ideal gas Equation

PV=nRT

where P=Pressure

V=volume

R=Universal Gas constant

T=Temperature

n=no of moles

as n and R is constant therefore

\frac{PV}{T}=constant

thus \frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{760}{760}\times \frac{298}{273}\times 22.4

V_2=24.45\ L

8 0
3 years ago
Sonic boom from a plane is an example of a shockwave. Give another example where a shockwave is produced
julia-pushkina [17]
Sonic boom can also be created from an atomic bomb going off.
7 0
4 years ago
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