Answer: 2.49×10^-3 N/m
Explanation: The force per unit length that two wires exerts on each other is defined by the formula below
F/L = (u×i1×i2) / (2πr)
Where F/L = force per meter
u = permeability of free space = 1.256×10^-6 mkg/s^2A^2
i1 = current on first wire = 57A
i2 = current on second wire = 57 A
r = distance between both wires = 26cm = 0.26m
By substituting the parameters, we have that
Force per meter = (1.256×10^-6×57×57)/ 2×3.142 ×0.26
= 4080.744×10^-6/ 1.634
= 4.080×10^-3 / 1.634
= 2.49×10^-3 N/m
Hi there!
This is an example of a recoil collision.
Using the conservation of momentum:
The initial momentum is 0 kgm/s (objects start from rest), so:
We are given that the 15 kg block has a velocity of 12 m/s to the left, so:
Solve for v2':
Answer:
24 m/s
Explanation:
Using v = u + at where u = initial velocity of the motorboat = 0 m/s (since the boat starts from rest), a = acceleration = 4 m/s², t = time = 6 s and v = velocity of the motorboat after 6.0 s.
Substituting the values of the variables into the equation, we have
v = u + at
= 0 m/s + 4 m/s² × 6.0 s
= 0 m/s + 24 m/s
= 24 m/s
