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dalvyx [7]
3 years ago
10

Write any two difference between CGS and MKS system of measurement ?​

Physics
1 answer:
Tresset [83]3 years ago
7 0

Answer:

MKS stands for Meter, Kilogram and second. In this system of unit mass is given in Kilogram, length in meter and time in second. ... CGS system stands for Centimeter- Gram- Second system. In CGS system, length is measured in centimeters mass is measured in grams and time is in seconds.

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A block is at rest on the incline shown in the gure. The coefficients of static and kinetic friction are 0.6 and 0.51, respec- t
Alekssandra [29.7K]

Normal reaction force on the block while it is at rest on the inclined plane is given as

F_n = mgcos\theta

here we know that

m = 46 kg

\theta = 29^o

now we will have

F_n = 46*9.8*cos29 = 394.3 N

now the limiting friction or maximum value of static friction on the block will be given as

F_s = \mu_s * F_n

F_s = 0.6 * 394.3 = 236.56 N

Above value is the maximum value of force at which block will not slide

Now the weight of the block which is parallel to inclined plane is given as

F_{||} = mg sin\theta

here we know that

F_{||} = 46*9.8 sin29 = 218.55 N

Now since the weight of the block here is less than the value of limiting friction force and also the block is at rest then the frictional force on the block is static friction and it will just counter balance the weight of the block along the inclined plane.

So here <u>friction force on the given block will be same as its component on weight which is 218.55 N</u>

5 0
3 years ago
Which word best describes the tone of the poem "Sir Isaac Newton"? A. magical B. mystical C. series D. humorous
erma4kov [3.2K]

a. magical i hope it help

6 0
3 years ago
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Which of the following is NOT a scientific hypothesis that can be studied?
Bezzdna [24]

Answer:

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A physical pendulum consists of a uniform solid disk (of radius R 2.35 cm) supported in a vertical plane by a pivot located a di
lutik1710 [3]

Answer:

T = 0.3658

Explanation:

The expression to use to calculate the period is the following:

T = 2π √I/Mgd (1)

Where:

I: moment of Innertia of pendulum

g: gravity acceleration (9.81 m/s²)

d: distance of the pivot

M: mass of the disk.

Before we do anything, we will find first the moment of Innertia of the pendulum.

This can be calculated with the following expression:

I = 1/2 MR² + Md² (2)

At the moment we don't have the mass of the disk, but we don't need it, we will express I in function of M, and then, it will be canceled with the M of expression (1). Calculating M we have (Remember that the units of radius and distance should be in meter):

I = 1/2 M(0.0235)² + M(0.0175)²

I = (2.76x10^-4)M + (3.06x10^-4)M

I = (5.82x10^-4)M (3)

Now, we will replace this value in equation (1):

T = 2π √(5.82x10^-4)M / (9.81)*(0.0175)M ---> Here M cancels out

T = 2π √(5.82x10^-4) / (9.81)*(0.0175)

T = 2π * 0.0582

T = 0.3658 s

This is the period of the pendulum

7 0
3 years ago
Define force and provide an example​
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Answer:

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