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mihalych1998 [28]
4 years ago
14

Facilitated diffusion and simple diffusion are processes that decrease the potential energy stored across a membrane true or fal

se
Physics
1 answer:
Anestetic [448]4 years ago
7 0

Answer:

It's true. Potential energy is actually the concentrations of different elements. Diffusion is the process of moving the elements or materials from the area of high concentration (high potential energy) to the low concentration. So in bot facilitated and simple types of diffusion the level of potential energy decreases across the membrane.

Explanation:

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Where do the animals you read about get the energy storage molecules they need to do the activities required for reproduction?
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From plants. Plants have starch and oils
6 0
3 years ago
Two parallel plates of equal area carry equal and opposite charge Q0. The potential difference between the two plates is measure
jonny [76]

Answer:

Q₁ > Qo

C₁ > Co

Explanation:

We know that

C_o=\dfrac{\varepsilon _oA}{d}

Lets take relative permitivity of green plate =k

So new capacitance value

C_1=k\dfrac{\varepsilon _oA}{d}

From above two expression we can say that

C₁ = kCo

k > 1

So we can say that

C₁ > Co

We also know that

Co = Qo V

C₁ = Q₁ V

From above we can say that

Co/C₁ =  Qo/Q₁             ( C₁ > Co ⇒Co/C₁ <1)

Co/C₁ <1

So we can say that

Qo/Q₁ < 1

Q₁ > Qo

3 0
3 years ago
___________ relates the quantities of pressure, volume, temperature, and quantitiy of moles.
Gnoma [55]
C.) The relationship between volume, temperature, pressure and quantity of moles is given by ideal gas law. Mathematically given by PV = nRT.
5 0
3 years ago
A 500 g ball swings in a vertical circle at the end of a 1.4-m-long string. when the ball is at the bottom of the circle, the te
sergij07 [2.7K]

A 500 g ball swings in a vertical circle at the end of a 1.4-m-long string. when the ball is at the bottom of the circle, the tension in the string is 18 n.

6 0
4 years ago
A man paddles a canoe at 6 km per hour. If he paddles on a river with a current of 6 km per hour, what is the speed of the canoe
Romashka-Z-Leto [24]

Answer:

If the canoe heads upstream the speed is zero. And directly across the river is  8.48 [km/h] towards southeast

Explanation:

When the canoe moves upstream, it is moving in the opposite direction of the normal river current. Since the velocities are vector (magnitude and direction) we can sum each vector:

Vr = velocity of the river = 6[km/h}

Vc = velocity of the canoe = -6 [km/h]

We take the direction of the river as positive, therefore other velocity in the opposite direction will be negative.

Vt = Vr + Vc = 6 - 6 = 0 [km/h]

For the second question, we need to make a sketch of the canoe and we are watching this movement at a high elevation. So let's say that the canoe is located in point 0 where it is located one of the river's borders.

So we are having one movement to the right (x-direction). And the movement of the river to the south ( - y-direction).

Since the velocities are vector we can sum each vector, so using the Pythagoras theorem we have:

Vt = \sqrt{(6)^{2} +(-6)^{2} } \\Vt=8.48[km/h]

5 0
3 years ago
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