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3 years ago

1. What is the wavelength of a sound wave with a frequency of 50 Hz, if the Speed of sound is 343 m/s.

Physics

1 answer:

marshall27 [118]3 years ago

7 0

1.6.86

2.59.04

3.3

Thats the answer I think

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The strength of gravitational force is dependent on the masses of and distance between two objects.

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4 years ago

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alekssr [168]

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2 years ago

A motorcycle that is slowing down uniformly. The motorcycle covers 1 ????m=1000 m in 80 sec⁡. The motorcycle then covers the nex

Lynna [10]

Answer:

Part a)

acceleration = -0.042 m/s/s

Part b)

initial speed = 14.17 m/s

final speed = 5.77 m/s

Explanation:

Part a)

Let the initial velocity of the motorcycle is

$v_i = v_o$

now at the end of 80 s let the speed is

$v_f = v_1$

after another 120 s let the speed will be

$v_f' = v_2$

now we know that

$d = \frac{v_i + v_f}{2} (t)$

$d = \frac{v_o + v_1}{2}(80)$

$1000 = 40(v_o + v_1)$

also we know that

$v_1 - v_o = a(80)$

also we have

$1000 = \frac{v_1 + v_2}{2}(120)$

$1000 = 60(v_1 + v_2)$

now we can say

$(v_2 + v_1) - (v_o + v_1) = \frac{50}{3} - \frac{50}{2}$

also we know

$v_2 - v_o = a(120 + 80)$

$-8.33 = 200 a$

$a = -0.042 m/s^2$

Part b)

now we have

$v_1 + v_o = 25$

$v_1 - v_o = (-0.042)(80)$

$v_1 = 10.83 m/s$

so the starting velocity of the trip is

$v_o = 25 - 10.83 = 14.17 m/s$

now speed after t = 200 s is given as

$v_2 = v_o + at$

$v_2 = 14.17 - (0.042)(200)$

$v_2 = 5.77 m/s$

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3 years ago

A gas-turbine power plant operating on the simple Brayton cycle has a pressure ratio of 7. Air enters the compressor at 0°C and

Ivahew [28]

Answer:

Answers of the Both parts are in the following attachment

Explanation:

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3 years ago

What multiple of the time constant τ gives the time taken by an initially uncharged capacitor in an RC series circuit to be char

podryga [215]

Answer:

t / τ₀ = 2.9

the time constant has to be multiplied by approximately three

Explanation:

The expression for long of a capacitor is

q = q₀ (1- e (-t/τ₀)

Where q is the charge and τ₀ is the time constant. What is found for when the initial capacitor charge at 63.5% (e⁻¹) of the maximum charge

In our case we are asked that the load be 94.5%, this means that

q/q₀ = 94.5%

q/q₀ = 0.945

Let's replace and calculate

q/q₀ = 1 - e (-t/τ₀)

0.945 = 1 - e (-t/τ₀)

(-t /τ₀) = ln (1 -0.945) = ln (0.055)

t / τ₀ = 2.9

the time constant has to be multiplied by approximately three for this charge

5 0

4 years ago