Answer:
254 °C
Explanation:
The average kinetic energy of gas molecules K = 3RT/2N where R = gas constant = 8.314 J/mol-K, N = avogadro's constant = 6.022 × 10²³ atoms/mol
T = temperature in Kelvin.
Let K be its average kinetic energy at t = -19°C = 273 + (-19) = 273 - 19 = 254 K = T. K = 3RT/2N = 3 × 8.314 J/mol-K × 254 K/(2 × 6.022 × 10²³ atoms/mol) = 5.26 × 10⁻²¹ J
When its average kinetic energy doubles, it becomes K₁ = 2K = 2 × 5.26 × 10⁻²¹ = 10.52 × 10⁻²¹ J at temperature T₂. So,
K₁ = 3RT₁/2N
T₁ = 2NK₁/3R
T₁ = 2 × 6.022 × 10²³ atoms/mol × 10.52 × 10⁻²¹ J/3 × 8.314 J/mol-K = 508 K
The temperature difference is thus ΔT = T₁ - T = 508 K - 254 K = 254 K.
Since temperature change in kelvin scale equals temperature change in Celsius scale ΔT = 254 °C
So, we need to change the temperature of the air by 254 °C to double its average kinetic energy.
A is the correct answer :D
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Answer:
joule
Explanation:
Let m = mass of the car and v1 = initial velocity and v2 = final velocity
Given.
Initial velocity = 100 km/h
final velocity = 50 km/h
What is work done in the car to slow it from 100km/h to 50km/h?
The work done in the car to slow it from v1 to v2.
w=Δk
joule.
Therefore, the work done is joule
Use. Weight = (mass)x(accel of gravity).
It'll be somewhere around approx roughly about in the neighborhood of 9.706667m/sec^2 .
