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LenKa [72]
3 years ago
11

A 6kg object speeds up from 5 m/s to 20 m/s. find p

Physics
2 answers:
kicyunya [14]3 years ago
6 0

as we know tha momentum is product of mass and velocityi.e p=mv but here in this question velocity changes from 5m/s to 20 m/s so here formula becomes

p=(final velocity -initial velocity )mass

so (20-5)6=90kgm/s ANS

mrs_skeptik [129]3 years ago
4 0

Momentum = mass x speed

The object's momentum is 30 kg-m/s at the beginning, 120 kg-m/s at the end, and its change in momentum is 90 kg-m/s .

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A mechanic needs to replace the motor for a merry-go-round. The merry-go-round should accelerate from rest to 1.5 rad/s in 6.0s
pashok25 [27]

Answer:

109656.25 Nm

Explanation:

\omega_f = Final angular velocity = 1.5 rad/s

\omega_i = Initial angular velocity = 0

\alpha = Angular acceleration

t = Time taken = 6 s

m = Mass of disk = 29000 kg

r = Radius = 5.5 m

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{1.5-0}{6}\\\Rightarrow \alpha=0.25\ rad/s^2

Torque is given by

\tau=I\alpha\\\Rightarrow \tau=\dfrac{1}{2}mr^2\alpha\\\Rightarrow \tau=\dfrac{1}{2}29000\times 5.5^2\times 0.25\\\Rightarrow \tau=109656.25\ Nm

The torque specifications must be 109656.25 Nm

5 0
3 years ago
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WARRIOR [948]
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8 0
3 years ago
An uncharged capacitor is connected to the terminals of a 4.0 V battery, and 6.0 μC flows to the positive plate. The 4.0 V batte
Ugo [173]

Answer:

1 μC extra charge will be flow here

Explanation:

Given data

battery V1 = 4.0 V

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we apply here principal of capacitor

that is Q directly proportional voltage

so we say Q2/Q1 = V2/ V1

put all value here

Q2/Q1 = V2/ V1

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Q2 = 7

so we see here 7 μC will be flow

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4 years ago
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Snezhnost [94]

Hi there!

Acceleration:

a = Δv / Δt, so:

a = 20/9 ≈ 2.22 m/s²

Displacement:

We can use the equation Δd = v₀t + 1/2at² to solve. (Initial velocity is 0).

Δd = 1/2at²

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3 years ago
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Softa [21]
The other name is displacement vessels
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5 0
3 years ago
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