All categories

3 years ago

A 6kg object speeds up from 5 m/s to 20 m/s. find p

2 answers:

6 0

as we know tha momentum is product of mass and velocityi.e p=mv but here in this question velocity changes from 5m/s to 20 m/s so here formula becomes

p=(final velocity -initial velocity )mass

so (20-5)6=90kgm/s ANS

mrs_skeptik [129]3 years ago

4 0

Momentum = mass x speed

The object's momentum is 30 kg-m/s at the beginning, 120 kg-m/s at the end, and its change in momentum is 90 kg-m/s .

You might be interested in

A 0.85 N force exists between a 7.1 * 10 ^ - 6 * C charge 5.4 m away. What is the magnitude of the second charge ? Please show w

katovenus [111]

Answer:

Explanation:

Force between charge is given by the following expression

F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .

Putting the given values ,

.85 = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²

Q₂ = .85 x 5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )

= .38788 x 10⁻³ C .

= 387.88 x 10⁻⁶ C .

4 0

3 years ago

A compound microscope is equipped with two objective lenses (10x and 45x) and has a 10x ocular lens. The highest magnification a

Wittaler [7]

Answer:

450X

Explanation:

When a specimen is been viewed, both

objective and ocular lenses works together so that the object is magnified.

From the question,objective lenses are;

1)10x

2)45x

ocular lens= 10x

Highest magnification

= 10X ocular × 45X objective

=450X

This implies that the image that was viewed will appear 450 times the actual size.

5 0

3 years ago

Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The lengt

Zanzabum

<span>Days and nights are equal in length everywhere.(gradpoint)</span>

8 0

3 years ago

Read 2 more answers

9. What do people playing pool use to determine their shots?

jek_recluse [69]

Angles, they line up their pool que with the pocket and make the shot

7 0

3 years ago

In a Broadway performance, an 84.5-kg actor swings from a R = 4.30-m-long cable that is horizontal when he starts. At the bottom

Arada [10]

Answer:

1.57772 m

Explanation:

M = Mass of actor = 84.5 kg

m = Mass of costar = 55 kg

v = Velocity of costar

V = Velocity of actor

$h_i$ = Intial height of actor = 4.3 m

g = Acceleration due to gravity = 9.81 m/s²

As the energy of the system is conserved

$\frac{1}{2}MV^2=Mgh_i\\\Rightarrow V=\sqrt{2gh_i}\\\Rightarrow V=\sqrt{2\times 9.81\times 4.3}\\\Rightarrow V=9.18509\ m/s$

As the linear momentum is conserved

$MV=(m+M)v\\\Rightarrow v=\frac{MV}{m+M}\\\Rightarrow V=\frac{84.5\times 9.18509}{84.5+55}\\\Rightarrow v=5.56372\ m/s$

Applying conservation of energy again

$\frac{1}{2}(m+M)v^2=(m+M)gh_f\\\Rightarrow h_f=\frac{v^2}{2g}\\\Rightarrow h_f=\frac{5.56372^2}{2\times 9.81}\\\Rightarrow h_f=1.57772\ m$

The maximum height they reach is 1.57772 m

3 0

3 years ago