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3 years ago

Write the solution to the given inequality in interval notation.

Mathematics

2 answers:

wlad13 [49]3 years ago

7 0

<h2>Answer:</h2>

The solution to the given inequality in interval notation is:

[-3,∞)

<h2>Step-by-step explanation:</h2>

The solution of the given inequality is the set of all the possible x values.

By looking at the graph which is a number line such that the shaded region is to the right of -3 and the arrow of solution goes to infinity and also there is a closed circle at -3.

This means that -3 is included in the solution set.

This means that the solution is all the real values which are greater than or equal to -3.

i.e. The solution is: x ≥ -3

i.e. [-3,∞)

brilliants [131]3 years ago

6 0

[-3, infinity)
It is greater than or equal to -3 and goes on to infinity

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BRAINLIEST TO CORRECT HURRY

dlinn [17]

Answer:

-5 5/10, -32/40,5

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3 years ago

Chelsea and her friends are making small fruit baskets for their neighbors. They have 90 pears, 45 peaches, and 75 apples. What

iVinArrow [24]

Answer:

15 baskets

Step-by-step explanation:

This question is a GCF question

The first step would be to find the factors of 45, 75 and 90

The factors of 45 are: 1, 3, 5, 9, 15, 45

The factors of 75 are: 1, 3, 5, 15, 25, 75

The factors of 90 are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

The greatest common factor is 15.

Therefore, the greatest number of baskets they can make if each basket has the same number of pears, the same number of peaches, and same number of apples, with no fruit leftover is 15 baskets

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3 years ago

Please help! A-level maths.

astra-53 [7]

$x+y=k\implies y=k-x$

Substitute this into the parabolic equation,

$k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0$

We're told the line $x+y=k$ intersects $C$ twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

$(-7)^2-4(k+3)=49-4(k+3)>0\implies k$

We can tell from the quadratic equation that $C$ has its vertex at the point (3, 6). Also, note that

$-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5$

and

$-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6$

so the furthest to the right that $C$ extends is the point (5, 2). The line $x+y=k$ passes through this point for $2+5=k\implies k=7$ . For any value of $k$ , the line $x+y=k$ passes through $C$ either only once, or not at all.