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3 years ago

Porcelain, paper, glass, and rubber are all examples of electrical

Chemistry

2 answers:

sveticcg [70]3 years ago

8 0

Answer:Insulators

Explanation:

Porcelain,Paper,glass and rubber are examples of Electrical insulators .

Insulators are those materials in which resistance to electric current is very high i.e. very small amount of electric current Flows through them .They are used in coating of wires.

Allisa [31]3 years ago

6 0

Electrical Insulators

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Mg+o2 balanced eaquation

Tanya [424]

Answer:

2Mg+O2=2MgO

balanced equation

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3 years ago

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Explain, in terms of energy, why the temperature of the reaction mixture increases

Dima020 [189]

Answer:

Magnesium reacts with dilute hydrochloric acid in a conical flask which is connected to an inverted measuring cylinder in a trough of water. The volume of hydrogen gas produced is measured over a few minutes, and the results are used to plot a graph........

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2 years ago

WILL MARK BRAINLIEST!!!!

Lyrx [107]

Answer:

5.702 mol K₂SO₄

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Compounds
Moles

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

Step 2: Identify Conversions

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})$
[DA] Divide [Cancel out units]: $\displaystyle 5.7015 \ mol \ K_2SO_4$

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

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3 years ago

Derive Boyle's law. i'll mark the brainliest for the answer

MArishka [77]

Answer:

According to Boyle's Law, an inverse relationship exists between pressure and volume. ... The relationship for Boyle's Law can be expressed as follows: P1V1 = P2V2, where P1 and V1 are the initial pressure and volume values, and P2 and V2 are the values of the pressure and volume of the gas after change.

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Explanation:

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3 years ago

Although both N2 and 02 are naturally present in the air we breathe, high levels of NO and NO2 in the atmosphere occur mainly in

joja [24]

Answer:

(a) Increasing the temperature adds heat which is a reactant shifting the equilibrium rightwards.

(b) Pressure has no effect since the change in the number of moles is zero.

Explanation:

Hello,

In this case, one could represent the given reaction as:

$N_2(g)+O_2(g)+ \Delta _rH \leftrightarrow 2NO$

Since it is endothermic. Thus, solving the (a) statement, one identifies the heat as a reagent, that is why the reaction cools down as it progress, therefore, by increasing the temperature, heat is added, that is, a reagent is added, which shifts the equilibrium rightwards, in other words, more NO is produced so its concentration increases.

Furthermore, for the (b) statement, since the change in the number of moles is zero, based on the stoichiometric coefficients as shown below:

$\Delta \nu =2-1-1=0$

Such value implies that the pressure has no effect on the concentration, taking into account the following form of the law of mass action:

$Kp=Kc(RT)^{\Delta \nu }$

Thus, since $\Delta \nu =0$ , $Kp=Kc$ , so no effect in concentration is due to the pressure.

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3 years ago