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bearhunter [10]
4 years ago
13

What’s the answer for number 2?

Chemistry
2 answers:
otez555 [7]4 years ago
6 0
Surface wave that is the answer
Lady bird [3.3K]4 years ago
4 0
The answer to this is surface wave i think
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Without doing any calculations, determine which of the following solutions would be most acidic.
Murljashka [212]

Answer:

In the first combination neutralization takes place to give a salt. So, solution 'a' is neutral in nature.

In the solution 'c', both salts are resulted by the combination of weak base and strong acid. The combination of these salts suppresses the acidity.

In last combination basic nature is observed due to the presence of CN⁻ ions. Thus, the solution 'd' is basic in nature.

Out of the five given solutions, 0.0100 M in HF and 0.0100 M in KBr is most acidic.  Therefore, solution 'b' is most acidic in nature.

Explanation:

5 0
4 years ago
List three organelles found in cells and describe their functions.
kozerog [31]

nucleus: controls cell

cell membrane: controls what goes in and out of a cell

cytoplasm: where chemical reactions take place

3 0
3 years ago
Read 2 more answers
Magnesium sulfate can be made by reacting magnesium metal with an acid . A gas is also produced . Name this gas
jekas [21]

Answer:

the answer to your question is

Explanation:

hydorgen

Mg+ H2SO4 --------> MgSO4 + H2

8 0
3 years ago
If scientists had tried to repeat thomosons experiment and found that they could not would thomosons cocnclusion still have been
lesantik [10]

Answer:

No

Explanation:

The conclusions from Thomoson's claims would be invalid if his experiment could not be replicated.

<em>One of the attributes of a valid experiment in science is replication. That is, an experiment must be repeatable with similar outcomes under similar conditions as the original experiment when independently performed by another scientist. Once an experiment cannot be replicated, the outcomes of such an experiment become invalid in science.</em>

Hence, <u>Thomoson's conclusion would be invalid if his experiment could not be replicated. </u>

5 0
3 years ago
Calculate the molar solubility of CaF2 in a 0.25 m solution of NaF(aq).
Kipish [7]

Answer:

6.4 × 10^-10 M

Explanation:

The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).

CaF2 will dissociate as follows:

CaF2 ⇌Ca2+ + 2F-

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

NaF will also dissociate as follows:

NaF ⇌ Na+ + F-

Where Na+ = 0.25M

F- = 0.25M

The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

8 0
3 years ago
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