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ryzh [129]
3 years ago
7

3x^2-x=10 Find factors Determine zeros

Mathematics
1 answer:
Sophie [7]3 years ago
7 0

Factors are (3x + 5) and (x - 2). Zeros are -5/3 and 2.

Step-by-step explanation:

  • Step 1: Given quadratic equation 3x² - x = 10 ⇒ 3x² - x - 10 = 0
  • Step 2: Use factoring method (product and sum rule) to find factors and zeros. So the equation can be written as below.

⇒ 3x² - 6x + 5x - 10 = 0

⇒ 3x(x - 2) + 5(x - 2) = 0

⇒ (3x + 5)(x - 2) = 0 These are the factors of the equation.

  • Step 3: Find zeros by equating the factors to 0.

⇒ 3x + 5 = 0 and x - 2 = 0

⇒ x = -5/3 and 2

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saul85 [17]

Answer:

36

Step-by-step explanation:

Let's let n be any number.

If we multiply n by 2, we get 2n. Since anything multiplied by 2 is even, 2n <em>must</em> be even. Therefore, let 2n be our first number.

So, the consecutive even number will be (2n+2) followed by (2n+4).

We know that their sum must be 114. Therefore, we can write the following equation:

(2n)+(2n+2)+(2n+4)=114

Solve for n. Combine like terms on the left:

6n+6=114

Subtract 6 from both sides:

6n=108

Finally, divide both sides by 6. Therefore, the value of n is:

n=108/6=18

Therefore, our first even number is 2n or 2(18) which equates to 36.

And the consecutive even numbers will be 38 and 40.

So, the smallest of them, the first term, is 36.

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3 years ago
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3 years ago
I need help with this problem right away please.
irga5000 [103]

Answer:

y= -1/9(x-1)^2 +2

Step-by-step explanation:

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We know the vertex form of a parabola is

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Substituting the vertex in

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We have another point, (-2,1)

Substitue this in with x=-2 and y =1.  This will let us find a

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Divide by 9

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Putting this back into the equation


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3 years ago
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Answer:

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Hi

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