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ryzh [129]
3 years ago
7

3x^2-x=10 Find factors Determine zeros

Mathematics
1 answer:
Sophie [7]3 years ago
7 0

Factors are (3x + 5) and (x - 2). Zeros are -5/3 and 2.

Step-by-step explanation:

  • Step 1: Given quadratic equation 3x² - x = 10 ⇒ 3x² - x - 10 = 0
  • Step 2: Use factoring method (product and sum rule) to find factors and zeros. So the equation can be written as below.

⇒ 3x² - 6x + 5x - 10 = 0

⇒ 3x(x - 2) + 5(x - 2) = 0

⇒ (3x + 5)(x - 2) = 0 These are the factors of the equation.

  • Step 3: Find zeros by equating the factors to 0.

⇒ 3x + 5 = 0 and x - 2 = 0

⇒ x = -5/3 and 2

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belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

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Based on my knowledge, you’d set both equations equal to y, and then set both sides equal to each other then solve.

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