Answer:
8 GRAMS OF OXYGEN WILL BE REQUIRED TO PRODUCE 9 GRAMS OF WATER MOLECULES.
Explanation:
The equation for the reaction is;
2 H + O2 ----> 2 H2O
(H = 1, O = 16)
From the reaction, it can be observed that 1 mole of O2 reacts to form 2 moles of H2O
At STP, using the molar masses of the elememts and compound in the reaction, 32 g of O2 will reacts to form 36 g (18 * 2 g) of H2O
32 g of O2 = 36 g OF H2O
if 9 grams of H2O is produced, the mass of oxygen required to produce it will be:
( 32 * 9 / 36 ) g of O2
= (288 / 36) g
= 8 g of O2
So, 8 grams of Oxygen will be required to produce 9 grams of water.
Answer:
Volume of water added = 2.0 L
Explanation:
Initial pH of the solution = 2.7
[H^+] concentration in 2 L solution of sulfuric acid,
![pH = -log[H^+]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%5E%2B%5D)
![[H^+] = 10^{-pH}\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%20%3D%2010%5E%7B-pH%7D%5C%20M)
![[H^+] = 10^{-2.7} = 0.001995\ M = 0.002\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%20%3D%2010%5E%7B-2.7%7D%20%3D%200.001995%5C%20M%20%3D%200.002%5C%20M)
Final pH of the solution = 3
Final [H^+] concentration of sulfuric acid,
![[H^+] = 10^{-pH}\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%20%3D%2010%5E%7B-pH%7D%5C%20M)
![[H^+] = 10^{-3} = 0.001\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%20%3D%2010%5E%7B-3%7D%20%3D%200.001%5C%20M)
Now,



Volume added = Final volume - Initial volume
= 4.0 - 2.0 = 2.0 L
The general rule followed is that if electronegativity difference is greater than 2, then it is considered an ionic bond. An ionic bond is a type of bond characterizing a transfer of electrons within a bond. Common examples are salts which adds that ionic bonds are common between a metal and a nonmetal. Therefore, the best answer from above is letter B.
Is the C because the mass in the compound is correct
Answer:
Eat food
Explanation:
Food contain protein, carbohydrates, fats etc. These nutrients undergoes metabolic process and produced energy in cellular respiration.
There are two types of respiration:
1. Aerobic respiration
2. Anaerobic respiration
Aerobic respiration
It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.
Glucose + oxygen → carbon dioxide + water + 38ATP
Anaerobic Respiration
It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.
Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide
This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.