Answer:
Cross-pollination
Explanation:
This technique is used to create new varieties, usually with stronger characteristics than the two original varieties. When the pollen of <u>one variety</u> is placed to a <u>different plant's stigma</u>, the resulting seeds create a new variety. This cross-pollination is used in plants of the same species.
Answer:
The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme
Explanation:
From the given information:
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.
In this same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;
Rate factor in the absence of catalyst:

Rate factor in the presence of catalyst:

Assuming the catalyzed reaction and the uncatalyzed reaction are taking place at the same temperature :
Then;
the ratio of the rate factors can be expressed as:

![\dfrac{k_2}{k_1}={ \dfrac {e^{[ Ea_1 - Ea_2 ] }}{RT} }}](https://tex.z-dn.net/?f=%5Cdfrac%7Bk_2%7D%7Bk_1%7D%3D%7B%20%20%5Cdfrac%20%7Be%5E%7B%5B%20%20Ea_1%20-%20Ea_2%20%5D%20%7D%7D%7BRT%7D%20%7D%7D)
Thus;

Let say the assumed temperature = 25° C
= (25+ 273)K
= 298 K
Then ;



The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme
Plant cells are rectangular or squarish in shape.
Plant cells have a large vacuole.
Answer:
The black snakes will survive and reproduce while the orange snakes die out.
Explanation:
The orange snakes will be easier to see by their prey and predators, and therefore will die out while the black snakes thrive because of their camouflage.
2. B. Weathering breaks rocks into minerals, and plants die and decay.
3. D. sand
4. B. silt
5. B. sand
Hope this helps!