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3 years ago

Engineers increase output in crop production by combining the strengths of

Chemistry

1 answer:

katrin [286]3 years ago

5 0

Answer:

Cross-pollination

Explanation:

This technique is used to create new varieties, usually with stronger characteristics than the two original varieties. When the pollen of one variety is placed to a different plant's stigma, the resulting seeds create a new variety. This cross-pollination is used in plants of the same species.

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What is the different between a mixture and a compound?

krek1111 [17]

A compound is 2 or more substances chemically combined, mixtures arent

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3 years ago

During the lab, you measured the pH of mixtures containing strong acid and strong base. Write net Brønsted equations that show t

jasenka [17]

Answer:

ClO⁻ + HC₂H₃O₂ ⇄ HClO + C₂H₃O₂⁻

Explanation:

Sodium hypochlorite is a strong electrolyte that ionizes in sodium cation and hypochlorite anion.

NaClO(aq) ⇒ Na⁺(aq) + ClO⁻(aq)

ClO⁻ is a base that reacts with acetic acid (HC₂H₃O₂) from vinegar (neutralization reaction).

ClO⁻ + HC₂H₃O₂ ⇄ HClO + C₂H₃O₂⁻

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3 years ago

Which list includes three types of chemical reactions?

Sidana [21]

Answer=3

Decomposition, double replacement, and synthesis are 3 types of chemical reactions.

7 0

3 years ago

Read 2 more answers

In nature, oxygen has three common isotopes. The atomic masses and relative abundances of these isotopes are given in the table

Vaselesa [24]

Answer: The average atomic mass of oxygen is 15.999 amu

Explanation:

Mass of isotope O-16 = 15.995 amu

% abundance of isotope O-16= 99.759 % = $\frac{99.759}{100}=0.99759$

Mass of isotope O-17 = 16.995 amu

% abundance of isotope O-17 = 0.037% = $\frac{0.037}{100}=0.00037$

Mass of isotope O-18 = 17.999 amu

% abundance of isotope O-18 = 0.204% = $\frac{0.204}{100}=0.00204$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(15.995\times 0.99759)+(16.995\times 0.00037)+(17.999 \times 0.00204)]$

$A=15.999$

Thus the average atomic mass of oxygen is 15.999 amu

5 0

3 years ago

The hybridization for the B in Bcl3 is ?

Phoenix [80]

Answer:

sp²

Explanation:

You need to look at how many electron orbitals around the atom. Looking at the structure below, you can see that there are three electron orbitals. This gives you an sp² hybridization.

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3 years ago