All categories

3 years ago

In what phase is the moon if it is gaining light and less than half illuminated

Chemistry

1 answer:

Nat2105 [25]3 years ago

7 0

Answer: Crescent

Explanation: Image result for In what phase is the moon if it is gaining light and less than half illuminated

Crescent Moons are when it's less than half illuminated, and gibbous when it's more than half. “Waxing” means that the Moon becomes more illuminated night-by-night, and the term “waning” means that it's getting less illuminated each night.

You might be interested in

According to the phase diagram for water, how is the state of water determined?

joja [24]

Explanation:

From the attached phase diagram, one can easily make out the phase in which water exists. Matter generally exists in three physical states which are solid, liquid and gas. Water is a unique compound that can exists in these three states at a given temperature and pressure.

From the attached phase diagram,

point O is the triple point where the three phases of pure substance co-exists.
The areas between the curves points at a single phase of matter. Y is a water vapor.
The lines on the curve denotes two equilibrium phases. For example; X is a phase contain ice and melt water.

Learn more:

brainly.com/question/1612862

#learnwithBrainly

3 0

3 years ago

Read 2 more answers

Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r

MakcuM [25]

Answer:

CH2O

Explanation:

Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.

C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

6 0

4 years ago

Read 2 more answers

SO42- 2NO2 H2OH2SO3 2NO3- In the above redox reaction, using oxidation numbers to identify the element oxidized, the element red

nignag [31]

Answer : In the redox reaction,

Nitrogen element is oxidized and sulfur element is reduced.

$NO_2$ act as reducing agent and $SO_4^{2-}$ act as an oxidizing agent.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

$SO_4^{2-}+2NO_2+H_2O\rightarrow H_2SO_3+2NO_3^-$

This reaction is a redox reaction in which nitrogen shows oxidation reaction because the oxidation state of 'N' changes from (+4) to (+5) and sulfur shows reduction reaction because the oxidation state of 'S' changes from (+6) to (+4).

In the redox reaction $NO_2$ act as reducing agent and $SO_4^{2-}$ act as an oxidizing agent.

6 0

4 years ago

If the pressure on a 1.04 L sample of gas is doubled at constant temperature, please compute the new volume of gas: __

natulia [17]

Answer:

0.52 L.

Explanation:

Let P be the initial pressure.

From the question given above, the following data were obtained:

Initial pressure (P1) = P

Initial volume (V1) = 1.04 L

Final pressure (P2) = double the initial pressure = 2P

Final volume (V2) =?

The new volume (V2) of the gas can be obtained by using the the Boyle's law equation as shown below:

P1V1 = P2V2

P × 1.04 = 2P × V2

1.04P = 2P × V2

Divide both side by 2P

V2 = 1.04P /2P

V2 = 0.52 L

Thus, the new volume of the gas is 0.52 L.

6 0

3 years ago

A certain phospholipid molecule contains two fatty acid chains of eight carbon atoms each having no carbon-carbon double bonds i

larisa [96]

Answer:

Here's what I get

Explanation:

The fatty acids form ester C-O bonds with the OH groups of glycerol and the phosphoric acid forms phosphate P-O bonds.

The phosphate also forms P-O ester linkages with the OH groups in other alcohols such as choline.

The structure below shows the phospholipid with two saturated C₈ fatty acids and the phosphate group.

5 0

3 years ago