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3 years ago

$20,000 for 14 years compounded at 8% semiannually results in how many periods

Mathematics

1 answer:

rjkz [21]3 years ago

3 0

13 months at $1501.00 per month

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You want to determine the average number of text messages that students at your school send in a month you want to collect data

trapecia [35]

I would go with football or hallway. If you choose footbal you would probably get a more random demographic but you might not get 200. If you choose hallways you could get 200 so hallway is probably more likely

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2 years ago

Y = x² - 4x convert from standard to vertex form

Pepsi [2]

Answer:

$y = (x-2)^{2} -4$

Step-by-step explanation:

To complete the square: add 4 to both sides because the product of 4 as 2 as the factor which 2 * 2 so $2^{2}$

$y + ? = x^{2} - 4x + ?$

$y + 2^{2} = x^{2} - 4x + 2^{2}$

$y + 4 = x^{2} - 4x + 4$

Now we can factor the expression

$y + 4 = (x-2)^{2}$

Move the 4 to the other side to isolate y which changes the sign

$y = (x-2)^{2} - 4$

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1 year ago

Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2

ankoles [38]

Option C:

$2 g^{3}-5 g^{2}+6$

Solution:

Given expression:

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

To find which expression is equal to the given expression.

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

Expand the term $-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12$

$$=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}$

Arrange the like terms together.

$$=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}$

$$=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}$

Factor the numerator $2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)$

$$=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}$

Cancel the common factor g + 2, we get

$=2 g^{3}-5 g^{2}+6$

Hence option C is the correct answer.

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