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seraphim [82]
3 years ago
9

What is the true solution to ln 20+ln 5= 2 ln x

Mathematics
2 answers:
Aleks [24]3 years ago
5 0
Ln20+ln5=2lnx
ln(20x5)=lnx^2
ln100=1nx^2
100=x^2
square root
x=10
Sonbull [250]3 years ago
3 0

Answer:

The true solution to the  \ln 20 + \ln 5 = 2 \ln x is, 10

Step-by-step explanation:

Given the equation: \ln 20 + \ln 5 = 2 \ln x

Using logarithmic rules:

  • \ln(mn) = \ln m+ \ln n
  • \ln a^b = b \ln a
  • ln a = \ln b ⇒a = b

Now, using these properties solve for x;

\ln (20 \cdot 5) = 2\ln x

\ln (100) = \ln x^2

\ln 10^2 = \ln x^2

On comparing both sides we have;

x^2 = 10^2

or

x = \sqrt{10^2}

x = 10

Therefore, the true solution to the given equation is, x= 10

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Answer: There are 16 fish that he can keep in the aquarium.

Step-by-step explanation:

Since we have given that

Length of aquarium = 4 feet

Width of aquarium = 1 foot

So, it forms a shape of cuboid.

As we know the formula for "Volume of Cuboid":

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According to question, Each fish needs atleast 0.5 cubic feet of water.

So, Number of fish that he can keep in the aquarium is given by

\frac{8}{0.5}=16

Hence, there are 16 fish that he can keep in the aquarium.

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