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3 years ago

13

Help please!!!!!!!!!!!!

1 answer:

olga nikolaevna [1]3 years ago

6 0

The answer is D because a proportional relationship on a graph would start on (0,0), so A and B cannot be the right answer. On answer C, the relationship starts as 4x=y but changes, so this cannot be a proportional relationship because the relationship needs to be constant. Answer D is the right answer because the proportional relationship remains constant (1.5x=y).

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Simplify 7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54

Katen [24]

$7\sqrt3-4\sqrt6+\sqrt{48}-\sqrt{54}\\\\=7\sqrt3-4\sqrt6+\sqrt{16\cdot3}-\sqrt{9\cdot6}\\\\=7\sqrt3-4\sqrt6+\sqrt{16}\cdot\sqrt3-\sqrt9\cdot\sqrt6\\\\=7\sqrt3-4\sqrt6+4\sqrt3-3\sqrt6\\\\=\boxed{11\sqrt3-7\sqrt6}$

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3 years ago

If 2 cups of ketchup= 1 cup of tomato sauce, then ____ cups of ketchup= 2.25 cups of tomato sauce.

SashulF [63]

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3 years ago

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serious [3.7K]

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Step-by-step explanation:

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3 years ago

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What is the missing statement in step 3 of the proof? mAngle1 = mAngle2 mAngle1 + mAngle2 = 90° mAngle2 = mAngle3 mAngle2 + mAng

zalisa [80]

Answer:

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3 years ago

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Express the following in exponential notation: (-4) x ... x (-4) 11 times

Anni [7]

Given:

The expression is:

$(-4)\times ...\times (-4) (11\text{ times})$

To find:

The exponential notation for the given expression.

Solution:

We know that

$a\times a\times ...\times a(n\text{ times})=a^n$ ...(i)

We have,

$(-4)\times ...\times (-4) (11\text{ times})$

Using (i), the given expression can be written as:

$(-4)\times ...\times (-4) (11\text{ times})=(-4)^{11}$

Therefore, the exponential notation of the given expression is $(-4)^{11}$ .

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2 years ago