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alexgriva [62]
3 years ago
13

Which equation applies the associative property of multiplication?

Mathematics
2 answers:
Radda [10]3 years ago
5 0

-5/12 x (6/5 x 1/3) x 9/2 = (-5/12 x 6/5) x (1/3 x 9/2) as said equation correlates with the following formula: (a x b) x c = a x (b x c) where the way you group three or more numbers when adding or multiplying does not change their overall sum or product. Hope this helped! :)

Feliz [49]3 years ago
4 0

Answer:

C.-\frac{5}{12}\cdot (\frac{6}{5}\cdot (\frac{1}{3})\cdot \frac{9}{2}=(-\frac{5}{12}\cdot \frac{6}{5})\cdot \frac{1}{3}\cdot \frac{9}{2})

Step-by-step explanation:

We have to find the equation in which associative property of multiplication is used.

Associative property of multiplication:

If a, b and c are number

Then, a\cdot (b.c)=(a\cdot b)\cdot c

A.(\frac{-7}{8}\cdot \frac{2}{5})+(\frac{-7}{8}\cdot \frac{3}{5})=-\frac{7}{8}\cdot (\frac{2}{5}+\frac{3}{5})

It is false because distributive property is used not associative property of multiplication.

B.(\frac{-1}{4}-\frac{5}{3})-\frac{3}{5}=-\frac{1}{4}-(\frac{5}{3}-\frac{3}{5})

It is false because associative property of multiplication is not used.

In option C

-\frac{5}{12}\cdot (\frac{6}{5}\cdot \frac{1}{3})\cdot \frac{9}{2}=(-\frac{5}{12}\cdot \frac{6}{5})\cdot (\frac{1}{3}\cdot \frac{9}{2})

It is true because associative property of multiplication is used.

In option D

\frac{-6}{7}\cdot \frac{8}{11}\cdot \frac{1}{3}=\frac{8}{11}\cdot \frac{-6}{7}\cdot \frac{1}{3}

It is not true because commutative property of multiplication is used not associative.

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Answer:

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slavikrds [6]

Answer:

Part B shaded below first line and above second line.

Step-by-step explanation:

The first inequality corresponds to the second line (-3 = -4+1, for example) The ≥ symbol in that inequality tells you it will be satisfied by y values above those on the line.

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Answer:

Step-by-step explanation:

First and foremost, all quadratics have a domain of all real numbers (as long as we are not given only a portion of the graph, or one with endpoints. Our graph does not have endpoints, so it is assumed that the tails will continue to go down into negative infinity and at the same time, the x coordinates will keep growing as well.) Since our quadratic is upside down, it has a max. That means that none of the values on the graph will be above that point. All the values will be below that highest point (the highest y-value). Y-values indicate range, and since our highest y-value is at y = 2, then the range is

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Answer:

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3 years ago
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