The mass of the car at the given kinetic energy is 920 kg.
The given parameters;
- initial velocity of the car, u = 22 m/s
- kinetic energy of the car, K.E = 222,640 J
Kinetic energy if the energy acquired by a body during its motion. This kinetic energy is the product of average velocity squared and mass of the object.
The mass of the car at the given kinetic energy is calculated as follows;
Thus, the mass of the car at the given kinetic energy is 920 kg.
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Answer:
D. the wind picking up dust and carrying it
Explanation:
Erosion is a process in which an agent transfer the top soil to another region, thereby exposing the lower soil. These agents have the ability to move the top layer of soil and deposit it at another place. The major agents in this case are; a running or flowing body of water and wind.
Therefore, the change to the Earth's surface that is an example of erosion is the wind picking up dust and carrying it. Thereby exposing the lower layers.
Answer:
vx = 65 yd/3 sec = 21.7 yd/sec since horizontal speed is constant
vy = g t = (32 / 3) yd/sec^2 * 1.5 sec = 16 yd/sec where 32/3 is the acceleration due to gravity in yds / sec^2 and 1.5 is the time to travel each way in the vertical direction
V = (vx^2 + vy^2)^1/2 = (21.7^2 + 16^2)^1/2 = 27 yd/sec
tan theta = vy/vx = 16 / 21.7 = .737 theta = 36.4 deg
You can check using the range formula:
R = v^2 sin (2 theta) / g = 27^2 * .955 / (32 / 3) = 65.3 yds
The difference from 65 yds may be rounding error.
Answer:
At the point when an item is moved into the air toward a path other than straight up or down, the speed, quickening, and uprooting of the article don't all point a similar way. In circumstances like this, when taking care of the difficult we ought to apply the procedure of settling vectors into segments. At that point we apply the more straightforward one-dimensional types of the conditions for every segment. At long last, we can recombine the parts to decide the resultant.
Explanation:
At the point when an item is moved into the air toward a path other than straight up or down, the speed, quickening, and uprooting of the article don't all point a similar way. In circumstances like this, when taking care of the difficult we ought to apply the procedure of settling vectors into segments. At that point we apply the more straightforward one-dimensional types of the conditions for every segment. At long last, we can recombine the parts to decide the resultant.
Objects that are tossed or dispatched into the air and are dependent upon gravity are called projectiles. The way of a shot is a bend called parabola. In the event that an article has an underlying speed in some random time span, there will be level movement all through the trip of the shot.
Shot movement is free fall with an underlying speed. The underlying flat speed of a shot is equivalent to the level speed all through the shot's flight.
To discover the speed go a shot anytime during its flight, discover the vector aggregate of the parts of the speed now. We should utilize the Pythagorean hypothesis to discover the extent of the speed and the digression capacity to discover the course of the speed. On the off chance that an article has an underlying vertical part of speed and a level segment of speed, the item's movement ought to be settled into its segments, and afterward the sine and cosine capacities can be utilized to locate the vertical and even segments of the underlying speed. The speed of a shot dispatched at a point to the ground has both flat and vertical parts. The vertical movement is like that of an item that is hurled straight with an underlying speed.
Answer:
502000W/m²
Heat flux = 800×50.2/20 =
502000W/m²
Explanation: