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4 years ago

When waves travel through water, why do the moving water particles continue to return to their starting position??

Physics

2 answers:

Alecsey [184]4 years ago

6 0

INFiNiTiV is correct! I just took the test on PLATO. The answer is C. Waves transfer energy, but not matter.

Law Incorporation [45]4 years ago

4 0

Waves transfer energy not matter. so simply put, the water doesn't move. it's just being used as a road that energy uses to get from point a to b. it's easier to think of some thing on the water rather than the water it self. like a cork floating on the surface. when a wave passes through the cork. the cork goes up to the peak of the wave and then down to the trough of the wave and then back at equilibrium. it only moved up and down since it was following the wave pattern. if the waves transfered matter as well as energy then the cork would begin to get pushed by the wave and move towards the direction of travel

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KonstantinChe [14]

Answer:

V = 19m/s

Explanation:

Given the following data;

Initial velocity, U = 4m/s

Acceleration, a = 0.5m/s²

Time, t = 30 seconds

To find the final velocity, we would use the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

V = 4 + 0.5*30

V = 4 + 15

V = 19m/s

Therefore, his final velocity is 19 meters per seconds.

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3 years ago

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MODERN PHYSICS

frosja888 [35]

Answer:

D. n=6 to n=2

Explanation:

Given;

energy of emitted photon, E = 3.02 electron volts

The energy levels of a Hydrogen atom is given as; E = -E₀ /n²

where;

E₀ is the energy level of an electron in ground state = -13.6 eV

n is the energy level

From the equation above make n, the subject of the formula;

n² = -E₀ / E

n² = 13.6 eV / 3.02 eV

n² = 4.5

n = √4.5

n = 2

When electron moves from higher energy level to a lower energy level it emits photons;

$E = E_0(\frac{1}{n_1^2}-\frac{1}{n_2^2} )\\\\\frac{1}{n_1^2}-\frac{1}{n_2^2} = \frac{E}{E_o} \\\\\frac{1}{4} -\frac{1}{n_2^2} = \frac{3.02}{13.6} \\\\\frac{1}{4} -\frac{1}{n_2^2} =0.222\\\\\frac{1}{n_2^2} = 0.25 - 0.22\\\\\frac{1}{n_2^2} = 0.03\\\\n_2^2 = 33.33\\\\n_2 = \sqrt{33.33} = 6$

For a photon to be emitted, electron must move from higher energy level to a lower energy level. The higher energy level is 6 while the lower energy level is 2

Therefore, The electron energy-level transition is from n = 6 to n = 2

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3 years ago

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Anettt [7]

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4 years ago

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Answer:

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3 years ago

6: A body throws a ball vertically up. It returns to the ground after 5 seconds. Find the velocity with which the ball is thrown

Elodia [21]

Answer:

Explanation:

Ball rises and falls in equal periods. Because it goes by same speeds and same route. Therefore t_{rise} = t_{fall} =2.5 s

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Here, we can find the height of the ball

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From the attaches V-t graphics, x=V.t/2

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4 years ago