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Natali5045456 [20]

3 years ago

11

When waves travel through water, why do the moving water particles continue to return to their starting position??

2 answers:

Alecsey [184]3 years ago

6 0

INFiNiTiV is correct! I just took the test on PLATO. The answer is C. Waves transfer energy, but not matter.

Law Incorporation [45]3 years ago

4 0

Waves transfer energy not matter. so simply put, the water doesn't move. it's just being used as a road that energy uses to get from point a to b. it's easier to think of some thing on the water rather than the water it self. like a cork floating on the surface. when a wave passes through the cork. the cork goes up to the peak of the wave and then down to the trough of the wave and then back at equilibrium. it only moved up and down since it was following the wave pattern. if the waves transfered matter as well as energy then the cork would begin to get pushed by the wave and move towards the direction of travel

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3 years ago

On the same spring day, a station near the equator has a surface temperature of 25°C, 15°C higher than the middle-latitude city

DedPeter [7]

Answer:

The air temperature at the tropopause is - 79 °C

Explanation:

We know that a station near the equator has a surface temperature of 25°C

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In order to find the air temperature at the tropopause we are going to deduce a linear function for the temperature at the tropopause.

This linear function will have the following structure :

$f(x)=ax+b$

Where '' $a$ '' and '' $b$ '' are real numbers.

Let's write $T(x)$ to denote the temperature '' T '' in function of the distance

'' x '' ⇒

$T(x)=ax+b$

We can reorder the function as :

$T(x)=b+ax$ (I)

Now, at the surface the value of '' $x$ '' is 0 km and the temperature is 25°C so in the function (I) we write :

$T(0)=25=b+a(0)$ ⇒ $b=25$ ⇒

$T(x)=25+ax$ (II)

In (II) the value of '' $a$ '' represents the change in temperature per kilometer.

Because the temperature decrease with the height this number will be negative and also a data from the question ⇒

$T(x)=25-(6.5)x$ (III)

In (III) we deduced the linear equation. The last step is to replace by $x=16$ in (III) ⇒

$T(16)=25-(6.5)(16)=-79$

The air temperature at the tropopause is - 79 °C

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3 years ago

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MAVERICK [17]

I think the answer would be
C.Electrons
Hope this helps

3 0

3 years ago

Read 2 more answers