Average speed = (distance covered) / (time to cover the distance)
= (30km + 40 km) / (25min + 35min)
= (70 km) / (60 min)
= 70 km/hour
For the temperature 321 K, the temperature is 118.13 degree Fahrenheit.
<u>Explanation:</u>
degree Fahrenheit = (K - 273.15) * (9/5) + 32
Fahrenheit is a thermodynamic temperature scale, where the freezing point of water is 32 degree Fahrenheit. Based upon the definitions of the Centigrade scale and the experimental evidence, the absolute zero is -273.15 degree Celsius.
degree Fahrenheit of 321 K = (321 - 273.15) * (1.8) + 32
= 118.13 degree Fahrenheit.
Answer:
2.1 rad(anticlockwise).
Explanation:
So, we are given the following data or parameters or information in the question above:
=> "The torsional stiffness of the spring support is k = 50 N m/rad. "
=> "If a concentrated torque of mag- nitude Ta = 500 Nm is applied in the center of the bar"
=> "L = 300 mm Assume a shear modu- lus G = 10 kN/mm2 and polar monnent of inertia J = 2000 mln"
Hence;
G × J = 10 kN/mm2 × 2000 mln = 20 Nm^2.
Also, L/2 = 300 mm /2 = 0.15 m (converted to metre).
==> 0.15/20 (V - w) + θ = 0.
==> 0.15/20 (V - w ) = -θ.
Where V = k = 50 N m/rad
w = 183.3 θ.
Therefore, w + Vθ = 500 Nm.
==> 183.3 + 50 θ = 500 Nm.
= 6.3
Anticlockwise,
θ = 2.1 rad.
A as the particles became cooler they lost energy and moved less resulting in less pressure on the balloon
Answer:
Explanation:
i) frequency is the square root of the quotient of Tension over linear density/ all divided by two times the length.
linear density and tension are constant, so the numerator remains constant
The length is doubled, so the frequency is halved.
f = 128 Hz
ii) Doubling the tension increases the frequency by √2
f = 256√2 = 362 Hz
2) If other factors remain constant, increasing tension increases frequency.
