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Art [367]
3 years ago
8

An astronaut in a spacecraft looks out her window and observes a comet travel in the opposite direction at a relative speed of 2

37 m/s. The velocity of the spacecraft is 114 m/s directly away from the sun. What is the comet's velocity relative to the sun? Assume that motion away from the sun is in the positive direction.
Physics
2 answers:
Sergeu [11.5K]3 years ago
7 0
The velocity of the spacecraft with respect to the Sun is
v_s = +114 m/s
the velocity of the comet in the reference system of the spacecraft is
v_c' = 237 m/s

So, the velocity of the comet in the reference system of the Sun will be
v_c = v_c'-v_s = -237 m/s - 114 m/s=-351 m/s
And the negative sign tells us that the comet is directed toward the Sun.
Umnica [9.8K]3 years ago
4 0

Answer: The relative velocity of the comet with respect to sun is '-351 m/s'.

Explanation:

Let the magnitude of the velocity of the spaceship moving away from the sun be |v_s|=114 m/s

Let the magnitude of the velocity of the comet moving towards the sun be |v_c| m/s

Assuming the direction away from the sun to be positive then :

The velocity of the space ship :v_s=+114 m/s

The  velocity of the comet :-v_c

v_r = relative velocity of spaceship with respect to comet

v_r=-237 m/s=v_s+(-v_c)=114 m/s-v_c

v_c=351 m/s

Velocity of the comet.v_c=351 m/s

v_R = Relative velocity of comet with respect to sun:

v_R=v_s+v_c=0 m/s+(-351 m/s)=-351 m/s

v_s= 0 m/s(Sun is fixed at one point)

The negative sign means that comet is moving towards the sun.The relative velocity of the comet with respect to sun is '-351 m/s'.

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Within a vacuum, the property to all electromagnetic waves is their
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Example 3 :
kherson [118]

The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.

<h3>How to determine the friction factor</h3>

Using the formula

μ = viscosity = 0. 06 Pas

d =  diameter = 120mm = 0. 12m

V =  velocity = 1m/s and 3m/s

ρ = density = 0.9

a. Velocity = 1m/s

friction factor = 0. 52 × \frac{0. 06}{0. 12* 1* 0. 9}

friction factor = 0. 52 × \frac{0. 06}{0. 108}

friction factor = 0. 52 × 0. 55

friction factor = 0. 289

b. When V = 3mls

Friction factor = 0. 52 × \frac{0. 06}{0. 12 * 3* 0. 9}

Friction factor = 0. 52 × \frac{0. 06}{0. 324}

Friction factor = 0. 52 × 0. 185

Friction factor = 0.096

Loss When V = 1m/s

Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter

Head loss = 0. 289 × \frac{1}{2*6. 6743 * 10^-11} × \frac{1^2}{0. 120} × \frac{1}{100}

Head loss =  1. 80 × 10^8

Head loss When V = 3m/s

Head loss = 0. 096 × \frac{1}{1. 334 *10^-10} × \frac{3^2}{0. 120} × \frac{1}{100}

Head loss = 5. 3× 10^8

Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss  when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.

Learn more about friction here:

brainly.com/question/24338873

#SPJ1

4 0
2 years ago
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