6 m.p.g if that's the type of question your referring to...
Answer:
6.25 or 6 1/4
Step-by-step explanation:
because 50 divided by 8 is 6.25
The answer is z = 3 + i
z = a + bi
conj(z) = a - bi
conj(7 + 3i) = 7 - 3i
<span>(conj)z + 2z = 2 + 4i + conj(7 + 3i)
</span>a - bi + 2(a + bi) =<span> 2 + 4i + 7 - 3i
</span>a - bi + 2a + 2bi =<span> 2 + 4i + 7 - 3i
</span>3a + bi = 9 + i
From here:
3a = 9 and bi = i
a = 9/3 b = i/i
a = 3 b = 1
z = a + bi
z = 3 + 1 * i
z = 3 + i
The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.
Domain is the values of x in the function represented by y=f(x), for which y exists.
THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".
Now we assume the
and 
So here since g(x) is a polynomial function so it exists for all real x.
<em> </em>does not exists when
, so the domain of f(x) is given by all real x except 6.
Now,

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.
But domain of both f(x) and g(x) consists of the value x=4.
Hence the statement is not TRUE universarily.
Thus the given statement about the composition of function is FALSE.
Learn more about Domain here -
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Answer:
3/4
Step-by-step explanation:
you need to find the change in x and y so you subtract the two x factors and the two y factors if you can simplify it then simplify