Answer:
1.) Displacement = 32.08m
2.) Velocity = 55km/h
3.) Acceleration = 94.29 km/h^2
Explanation:
Given that the train takes 35 minutes to cover the distance between the two towns. The train's average speed is 55 kilometers per hour. That is,
Time t = 35 minute
Convert it to hours by dividing it by 60
35/60 = 7/12 hours
Speed = 55 km/h
The displacement of the car is:
Displacement = 55 × 7/12 = 32.08 m
The velocity of the car will be 55 km/h
The acceleration of the car will be:
Acceleration = velocity/time
Substitute velocity and time into the formula
Acceleration = 55 ÷ 7/12
Acceleration = 94.29 km/h^2
Answer:
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Answer:
μs = 0.75
μk = 0.58
Explanation:
From a force diagram:
(1)
(2)
When it starts slipping, friction force is the maximum and acceleration is 0. Replacing these conditions on (1):
Solving for μs:

μs = tan 36.7° = 0.75
When it moves at constant speed, friction force is kinetic friction and acceleration is 0. With these conditions the coefficient is:
μk = tan 30.1° = 0.58