The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.
<h3>Change in energy level of the electron</h3>
When photons jump from a higher energy level to a lower level, they emit or radiate energy.
The change in energy level of the electrons is calculated as follows;
ΔE = Eb - Ef
ΔE = -2.68 eV - (-5.74 eV)
ΔE = 3.06 eV
Thus, the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.
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Answer:
mass = 9.7 kg
Explanation:
Weight = Mass x Acceleration due to gravity (g)
16.5 = mass x 1.7
mass = 
= 9.7 kg
Answer:
Slower
Explanation:
Slower because the air would be pushing you back, and the other person would be walking faster because they are being pushed forward by the wind
