I think every 6 hours would be correct
The period is simply the inverse of the frequency, therefore:
T = 1 / f
T = 1 / 775 Hz
T = 0.001290 s → possible answer
T = 1.29 × 10⁻³ s → possible answer
T = 1.29 ms → possible answer
Answer:
30.96 m
Explanation:
If the particle has a lifetime of 129 ns as measured by observer A, and has a speed of 0.8c as measured by observer A, the distance between the markers will be:
d = v * Δt
v = 0.8*c = 0.8 * 3e8 = 2.4e8
Δt = ζ = 129 ns = 1.29e-7 s
d = 2.4e8 * 1.29e-7 = 30.96 m
This is the distance as measured by observer A.
It is a barred spiral galaxy.
