Question

A pizza restaurant sold 24 cheese pizzas and 16 pizzas with one or more toppings. Twelve of the cheese pizzas were eaten, and 10 of the pizzas with one or more toppings were eaten at work. If a pizza was selected at random, find the probability of each:a. It was a cheese pizza eaten at work.b. It was a pizza with either one or more toppings, and it was not eaten at work.c. It was a cheese pizza, or it was a pizza eaten at work.

Answer 1

Answer:

Step-by-step explanation:

                                cheese  With toppings    Total

No of pizzas sold    24                     16                40

Eaten at work           12                     10                22

Not eaten at work     12                      6                18

a) Prob for a cheese pizza eaten at work=$\frac{12}{40} =0.30$

b) Prob a pizza with either one or more toppings, and it was not eaten at work.=$\frac{6}{40} =0.15$

c) Prob for a cheese pizza, or it was a pizza eaten at work.=P(cheese)+P(pizza eaten at work)-P(both)

= $\frac{24}{40} +\frac{22}{40} -\frac{12}{40} \\=\frac{34}{40} \\=0.85$