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3 years ago

1/3 greater than 1/4

Mathematics

2 answers:

denis-greek [22]3 years ago

8 0

Yes, Because 1/3 makes up four and 1/4 makes up 3

Allisa [31]3 years ago

6 0

Yes, 1/3 is greater than 1/4. 1/3= 33.3% and 1/4= 25%

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Find the surface area of the hemisphere 6cm

lina2011 [118]

Answer:

452.4 cm^2

Step-by-step explanation:

$a = 4\pi {r}^{2} \\ a = 4 \pi \times (6)^{2} \\ a = 452.4 \: cm^{2}$

I hope that is useful for you :)

7 0

3 years ago

this rectangular prism is cut by the plane shown. The plane is perpendicular to the base of the rectangular prism. What is the s

Musya8 [376]

Answer: REACTANGLE !!!!!!!!!!!

Step-by-step explanation:

The shape of the cross-section is a rectangle. The plane is perpendicular to the base of the rectangular prism so the shape of the cross-section is the same as the top and bottom views of the rectangular prism.

4 0

3 years ago

Read 2 more answers

zubka84 [21]

Answer:

See Explanation Below

Step-by-step explanation:

Given

$(sin x - cos x)^2 = sec^2x - tan^2x - 2sinx.cos x.$

Required

Prove

To start with; we open the bracket on the left hand side

$(sin x - cos x)^2 = (sin x - cos x)(sin x - cos x)$

$(sin x - cos x)^2 = (sin x )(sin x - cos x)- (cos x)(sin x - cos x)$

$(sin x - cos x)^2 = sin^2 x -sinx cos x - sin xcos x + cos^2 x$

$(sin x - cos x)^2 = sin^2 x -2sinx cos x + cos^2 x$

Reorder

$(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x$

From trigonometry;

$sin^2x + cos^2x = 1$

So;

$(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x$

becomes

$(sin x - cos x)^2 = 1 - 2sinx cos x$

Also from trigonometry;

$sec^2x - tan^2x = 1$

So,

$(sin x - cos x)^2 = 1 - 2sinx cos x$

becomes

$(sin x - cos x)^2 = sec^2x - tan^2x - 2sinx cos x$

Proved

3 0

3 years ago

Solve the equation.<br><br> 4^2x – 5 = 64

KiRa [710]

X= 4.3125 or x= 4.313

7 0

3 years ago

Read 2 more answers

How do I solve this?

charle [14.2K]

Answer:

find all numbers, stick together o make an uqaion and solve . simplifi if needed

Step-by-step explanation:

6 0

2 years ago