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Zolol [24]
3 years ago
5

During each cycle, a refrigerator ejects 610 kJ of energy to a high-temperature reservoir, and takes in 505 kJ of energy from a

low-temperature reservoir. (a) Determine the work done on the refrigerant in each cycle. kJ (b) Determine the coefficient of performance of the refrigerator.
Physics
1 answer:
jenyasd209 [6]3 years ago
8 0

Answer

A. the work done on the refrigerant in each cycle is 105kJ

B the coefficient of performance of the refrigerator is 4.8

Explanation

Given data

Work done at high temperature T2 Qh=610kJ

Work done at low temperature T1 Ql=505kJ

We know that the net work done by the refrigerator is expressed as

Wnet= Qh-Ql

=610-505

=105kJ

Also we know that the coefficient of performance is expressed as

COP= Ql/Wnet

COP= 505/105

= 4.8

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irina [24]
D I know this is right
5 0
3 years ago
In Trial III, a different, looser, spring is used; its force constant is 23.1 N/m. The suspended mass is the same as the one in
cricket20 [7]

Answer:

T=0.827s

Explanation:

The period of a spring can be calculated with the equation

T=2\pi w

But we know as well that w is given by,

w=\sqrt{\frac{k}{m}}

Replacing,

w=\frac{2\pi}{T}= \sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{0.4}{23.1}}

So we have that

T=0.827s

7 0
3 years ago
One ball is dropped vertically from a window. At the same instant, a second ball is thrown horizontally from the same window.
geniusboy [140]

Answer:

The second ball

Explanation:

Both balls are under the effect of gravity, accelerating with exactly the same value. The first ball is dropped, therefore its initial velocity is zero. Since the second ball has horizontal and vertical velocity components, its initial velocity is given by:

v=\sqrt{v_x^2+v_y^2}

The vertical component is zero, however, it has a horizontal velocity, so its initial speed is not zero, therefore the secong ball has the greater speed at ground level.

7 0
3 years ago
A motor requires 400 joules of energy to lift a 5.0 kg mass 2.0 meters. Calculate the efficiency of this motor.
Sauron [17]

Answer:

25%

Explanation:

use F=mg

then use the answer you get from that and plug it into W=Fxh

take that answer and divide it by 400 J and multiply by 100

round to sig figs

4 0
3 years ago
A skateboarder, with an initial speed of 2.0 m/s, rolls virtually friction free down a straight incline of length 18 m in 3.3 s.
lesya692 [45]

Initial speed of the skateboarder (u) = 2 m/s

Distance covered (s) = 18 m

Time taken = 3.3 seconds

Let the acceleration be a.

Using seconds equation of motion:

s = ut + \frac{1}{2} a t^2

18 = 2 \times 3.3 + \frac{1}{2}a \times 3.3^2

a = \frac{11.4 \times 2}{10.89}

a = 2.09 m/s^2

Now, Acceleration down the incline = g Sin Θ

g Sin Θ = a

9.8 × Sin Θ = 2.09

Sin Θ = \frac{2.09}{9.8}

Θ = 12.31°

Hence, the angle of the inclined plane is: Θ = 12.31°

4 0
3 years ago
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