Answer:
Approximately 
to the right (assuming that both astronauts were originally stationary.)
Explanation:
If an object of mass 
is moving at a velocity of 
, the momentum 
of that object would be 
.
Since momentum of this system (of the astronauts) conserved:
.
Assuming that both astronauts were originally stationary. The total initial momentum of the two astronauts would be 
since the velocity of both astronauts was 
.
Therefore:
.
The final momentum of the first astronaut (
, 
to the left) would be 
to the left.
Let 
denote the momentum of the astronaut in question. The total final momentum of the two astronauts, combined, would be 
.
.
Hence, 
. In other words, the final momentum of the astronaut in question is the opposite of that of the first astronaut. Since momentum is a vector quantity, the momentum of the two astronauts magnitude (
) but opposite in direction (to the right versus to the left.)
Rearrange the equation to obtain an expression for velocity in terms of momentum and mass: 
.
.
Hence, the velocity of the astronaut in question (
) would be to the right.
Answer:
0.56 km/s
Explanation:
We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.
![560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s]](https://tex.z-dn.net/?f=560%5B%5Cfrac%7Bcm%7D%7Bs%7D%5D%2A%28%5Cfrac%7B1m%7D%7B100cm%7D%20%29%3D5.6%5Bm%2Fs%5D%5C%5C0.56%5B%5Cfrac%7Bkm%7D%7Bs%7D%5D%2A%28%5Cfrac%7B1000m%7D%7B1km%7D%20%29%3D560%5Bm%2Fs%5D)
Therefore the speed of 0.56 [km/s] is the greatest of all
Answer: A constellations
Explanation: hope it helps
M1 v1 = (m1 + m2)v2.
All of the exponents should be lowered to the bottom right of the letters.
W = F x d/x = (m x Ag) x h, therefore, mass (2kg x 9.8) x 2.5m = 49J
