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dsp73
3 years ago
15

un jugador de beisbol batea un foul recto en el aire.la pelota deja el bate con una rapidez de 120 km/h. en ausencia de resisten

cia del aire. ¿cual sera la rapidez de la pelota cuando la atrape el catcher
Physics
1 answer:
lina2011 [118]3 years ago
3 0

Answer:

120 km/h

Explanation:

This is a case of a parabolic motion. For this kind of motion the horizontal component of the velocity does not change in the complete trajectory. That is:

v_x=constant

Then, the velocity of the ball at the moment in which the catcher caught the ball is:

v=120\frac{km}{h}

the velocity of the ball is 120 km/h.

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7 0
3 years ago
A force in the +x-direction with magnitude ????(x) = 18.0 N − (0.530 N/m)x is applied to a 6.00 kg box that is sitting on the ho
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v_f=8.17\frac{m}{s}

Explanation:

First, we calculate the work done by this force after the box traveled 14 m, which is given by:

W=\int\limits^{x_f}_{x_0} {F(x)} \, dx \\W=\int\limits^{14}_{0} ({18N-0.530\frac{N}{m}x}) \, dx\\W=[(18N)x-(0.530\frac{N}{m})\frac{x^2}{2}]^{14}_{0}\\W=(18N)14m-(0.530\frac{N}{m})\frac{(14m)^2}{2}-(18N)0+(0.530\frac{N}{m})\frac{0^2}{2}\\W=252N\cdot m-52N\cdot m\\W=200N\cdot m

Since we have a frictionless surface, according to the the work–energy principle, the work done by all forces acting on a particle equals the change in the kinetic energy of the particle, that is:

W=\Delta K\\W=K_f-K_i\\W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}

The box is initially at rest, so v_i=0. Solving for v_f:

v_f=\sqrt{\frac{2W}{m}}\\v_f=\sqrt{\frac{2(200N\cdot m)}{6kg}}\\v_f=\sqrt{66.67\frac{m^2}{s^2}}\\v_f=8.17\frac{m}{s}

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3 years ago
A) An automobile light has a 1.0-A current when it is connected to a 12-V battery. Determine the resistance of the light.
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Answer:

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(A)

Current I = 1 A

Voltage V = 12 V

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  V = IR

  R = \frac{V}{I}

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  R = 12Ω

(B)

For finding power delivered,

  P = I^{2} R

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  P = 12 Watt

(C)

For finding the potential difference,

   V = IR

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   V = 10 \times 10^{-3}

   V = 0.01 V

Therefore, the resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

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