Answer:
Answer:
Propotionality is important
Explanation:
Explanation:
Answer:
20.0 cm
Explanation:
Here is the complete question
The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?
Solution
Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.
Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.
Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m
Now, P' = 1/u + 1/v
1/u = P'- 1/v
1/u = 55.0 D - 1/0.02 m
1/u = 55.0 m⁻¹ - 1/0.02 m
1/u = 55.0 m⁻¹ - 50.0 m⁻¹
1/u = 5.0 m⁻¹
u = 1/5.0 m⁻¹
u = 0.2 m
u = 20 cm
So, at 55.0 dioptres, the closet object she can see is 20 cm from her eye.
Answer:
Moses had told them to not keep the food till morning but some kept some anyways because they probably thought they were going to starve or not have food the next morning but what I think it means is that you have to trust in God that he will provide for you and so when the people kept the food cuz he thought they were probably going to start of the next day it got maggots
Answer:
(a) v = 65.35 m/s
(b) ac = 82.16 m/s²
Explanation:
Kinematic of the blades of the wind turbine
The blades of the wind turbine describe circular motion and the formulas that apply to this movement are as follows:
v = ω * R Formula (1)
Where:
v : tangential velocity (m/s)
ω : angular velocity (rad/s)
R : radius of the particle path (m)
The velocity vector is tangent at each point to the trajectory and its direction is that of movement. This implies that the movement has centripetal acceleration (ac):
ac = ω²* R Formula (1)
ac : centripetal acceleration (m/s²)
Data:
ω= 12 rpm = 12 rev/min
1 rev = 2π rad
1 min = 60 s
ω= 12 rev/min = 12 (2π rad)/(60 s)
ω = 1.257 rad/s
R = 52 m
(a)Tangential velocity at the tip of a blade (v)
We apply the formula (1)
v = ω* R
v = ( 1.257)* (52) = 65.35 m/s
(a) Centripetal acceleration at the tip of a blade (ac)
We apply the formula (2)
ac = ω²*R
ac = ( 1.257)²* (52) = 82.16 m/s²
