That two particles (fermions ie. neutrons protons electrons) mustn't have a bunch of identical quantum numbers.
Answer:
ΔT = 98.84 °C
Explanation:
Given data:
Heat absorbed = 255 J
Mass of gold = 20.0 g
Specific heat capacity of gold = 0.129 J/g.°C
Temperature change = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
by putting values,
255 J = 20.0 g × 0.129 J/g.°C × ΔT
255 J = 2.58 J / °C × ΔT
ΔT = 255 J / 2.58 J / °C
ΔT = 98.84 °C
Answer:
when it comes to adding or subtracting numbers, his final answer should have the same number of decimal places as the least precise value.
For example if you add 2 numbers; 10.443 + 3.5 , 10.443 has 3 decimal places and 3.5 has only one decimal place.
Therefore 3.5 is the less precise value.
So when adding these 2 values the final answer should have only one decimal place.
after adding we get 13.943 but it can have upto one decimal place. then the second decimal place is less than 5 so the answer should be rounded off to 13.9.
the answer is the same number of decimal places as the least precise value
Explanation:
I think this is the answer I'm not sure
"In autumn, the amount of ethylene decreases, rendering the cells of the abscission layer more sensitive to auxin" is the one that explains <span>the reason for this behavior. The correct option among all the options that are given in the question is the first option or option "A". I hope it helps you.</span>
Complete Question
A guest orders a drink that contains 4 1/2 ounces of 80-proof liquor. Approximately how many drinks does this beverage contain?
Answer:
![No\ of\ drinks =3](https://tex.z-dn.net/?f=No%5C%20of%5C%20drinks%20%3D3)
Explanation:
From the question we are told that:
Ordered drink 4 1/2 ounces of 80-proof liquor
Generally
80-proof liquor contains 40\% alcohol
Giving the drink a standard 1.5 ounce of distilled spirit
Therefore
![No\ of\ drinks =\frac{4.5}{1.5}](https://tex.z-dn.net/?f=No%5C%20of%5C%20drinks%20%3D%5Cfrac%7B4.5%7D%7B1.5%7D)
![No\ of\ drinks =3](https://tex.z-dn.net/?f=No%5C%20of%5C%20drinks%20%3D3)