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3 years ago

Substances that are readily combustible or may cause fire through friction

Chemistry

1 answer:

Dvinal [7]3 years ago

3 0

Answer :

Flammable substances

Explanation :

Flammable substances will catch fire and continue to burn when they contact an ignition source like a spark or a flame.

For example, methanol is a flammable liquid.

A flammable solid may also catch fire through friction. Matches are flammable solids.

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Jlenok [28]

Answer:

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3 years ago

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Answer:

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3 years ago

A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num

-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

$V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}$

$\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}$

B) Radius

$\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}$

$V = \frac{ 4}{3 }\pi r^{3}$

$r^{3} = \frac{3V }{4 \pi }\$

$r= \sqrt [3]{ \frac{3V }{4 \pi } }$

$r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}$

3 0

3 years ago

100 POINTS PLEASE HELP (PHOTOS INCLUDED)

pshichka [43]

Answer:

Explanation:

Knowns: 100mL of solution; concentration of 0.7M

Unknown: number of moles

Equation: number of moles = volume * concentration

Plug and Chug: number of moles = 100/1000 * 0.7 = 0.07 mole

Final Answer: 0.07mole

Knowns: 5.50L of solution; concentration of 0.400M

Unknown: number of moles

Equation: number of moles = volume * concentration

Plug and Chug: number of moles = 5.5 * 0.4 = 2.20 mole

Final Answer: 2.20 mole

6 0

2 years ago

Read 2 more answers

. Find the mass of 0.159 mol silicon dioxide.

Juliette [100K]

Answer:

9.55 grams of SiO2

Explanation:

If the mass you mean by grams:

0.159 mole x 60.08 g (Periodic table by adding both elements)

Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:

9.55 grams of SiO2

4 0

3 years ago