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3 years ago

Substances that are readily combustible or may cause fire through friction

Chemistry

1 answer:

Dvinal [7]3 years ago

3 0

Answer :

Flammable substances

Explanation :

Flammable substances will catch fire and continue to burn when they contact an ignition source like a spark or a flame.

For example, methanol is a flammable liquid.

A flammable solid may also catch fire through friction. Matches are flammable solids.

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A155-g sample of a unknown substance was heated from 25.0°C to 40.0°C.In the process, the substance absorbed 5696 J of energy. W

Iteru [2.4K]

The answer is: (5696 J) / (155 g) / (40.0 - 25.0)°C = 2.45 J/g·°C

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4 years ago

Consider a reactant with an order of 1: What effect does that reactant have on the rate equation when the concentration is doubl

____ [38]

Answer:

1) The reaction rate is double with respect to that reactant

Explanation:

Hello,

By considering the rate law:

$-r_A=kC_A$

If we double the reactant A concentration, by definition, the rate will be doubled as well since the $C_A$ power is one (order 1), this could be proved just by checking it out in the rate law.

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3 years ago

Which of the following most likely happens when the number of particles of a gas decreases?

Papessa [141]

Answer: C. The number of collisions of gas particles decreases

Explanation: As temperature decreases so does everything else same with increase.

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3 years ago

Calculate the pH of a 0.50 M HIO. The Ka of hypoiodic acid, HIO, is 2.3x10–11.0.305.325.479.474.80

never [62]

Answer:

pH = 5.47

Explanation:

The equilibrium that takes place is:

HIO ↔ H⁺ + IO⁻

Ka = $\frac{[H+][IO-]}{[HIO]}$ = 2.3 * 10⁻¹¹

At equilibrium:

[HIO] = 0.5 M - x

[H⁺] = x

[IO⁻] = x

Replacing those values in the equation for Ka and solving for x:

$Ka=\frac{x^2}{0.5-x}=2.3*10^{-11} \\x^2=(2.3*10^{-11})(0.5-x)\\x^2=1.15*10^{-11}-2.3*10^{-11}x\\x^2+2.3*10^{-11}x-1.15*10^{-11}=0\\x=3.39*10^{-6}$

Then [H⁺]=3.39 * 10⁻⁶, thus pH = 5.47

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3 years ago

rite stepwise equations for protonation or deprotonation of this polyprotic species in water. What are the products of the first

adoni [48]

Answer: The products of the given chemical equation are $HCO_3^-\text{ and }OH^-$

Explanation:

Protonation equation is defined as the equation in which protons get added in the substance.

The chemical equation for the protonation of carbonate ion in the presence of water follows:

$CO_3^{2-}+H_2O\rightarrow HCO_3^-+OH^-$

By Stoichiometry of the reaction:

1 mole of carbonate ion reacts with 1 mole of water to produce 1 mole of hydrogen carbonate ion and 1 mole of hydroxide ion

Hence, the products of the given chemical equation are $HCO_3^-\text{ and }OH^-$

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3 years ago