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Vadim26 [7]
3 years ago
14

Is change in atmospheric co2 levels likely to impact marine life

Chemistry
1 answer:
Murljashka [212]3 years ago
4 0

The addition of carbon dioxide to the atmosphere takes place due to human activities like the burning of fossil fuels. The oceans play an essential role in maintaining the carbon cycle of the Earth in balance. With the elevation of carbon dioxide in the atmosphere, more absorption of carbon dioxide takes place by the oceans.  

In the ocean, carbon dioxide reacts with seawater to produce carbonic acid, this ultimately leads to an increase in acidity of seawater, also known as ocean acidification.  

With the increase in acidity, it becomes tougher for corals to construct skeletons and for shellfish and other creatures to manufacture the shells they require for protection. The corals are mainly essential as they offer habitation to various sea creatures.  


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Sterling silver is 92.5% silver and 7.5% copper. Its density is 10.25 g/cm3. A sterling silver pendant is added to a graduated c
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From the information given:

  • The volume of the graduated cylinder = 50.0 mL
  • when a sterling silver pendant is added, the volume increases to = 61.3 mL

∴

The volume of the sterling silver pendant is:

= 61.3 mL - 50.0 mL

= 11.3 mL

Since, 1 mL = 1cm³

Then;

11.3 mL = 11.3 cm³

  • the density of the sterling silver = 10.25 g/cm³

Using the relation for Density; i.e.

\mathbf{Density = \dfrac{mass}{volume}}

\mathbf{10.25 \ g/cm^3= \dfrac{mass}{11.3  \ cm^3}}

mass = 10.25 g/cm³× 11.3 cm³

mass of the sterling silver = 115.825 grams

Recall that sterling silver has:

  • 92.5% silver and;
  • 7.5% copper

∴

The mass of the copper contained in the sterling silver pendant can be calculated as:

\mathbf{= \dfrac{115.825  \ g \times 7.5}{100}}

= 8.687 grams

Therefore, we can conclude that the mass of the copper contained in the sterling silver pendant is 8.687 grams

Learn more about the relation between Density, Mass, and Volume here:

brainly.com/question/24386693?referrer=searchResults

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