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Vadim26 [7]
3 years ago
14

Is change in atmospheric co2 levels likely to impact marine life

Chemistry
1 answer:
Murljashka [212]3 years ago
4 0

The addition of carbon dioxide to the atmosphere takes place due to human activities like the burning of fossil fuels. The oceans play an essential role in maintaining the carbon cycle of the Earth in balance. With the elevation of carbon dioxide in the atmosphere, more absorption of carbon dioxide takes place by the oceans.  

In the ocean, carbon dioxide reacts with seawater to produce carbonic acid, this ultimately leads to an increase in acidity of seawater, also known as ocean acidification.  

With the increase in acidity, it becomes tougher for corals to construct skeletons and for shellfish and other creatures to manufacture the shells they require for protection. The corals are mainly essential as they offer habitation to various sea creatures.  


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Anit [1.1K]
The answer is B..............
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A lahar is a type of mudflow that occurs
Fittoniya [83]
I'd guess A or D, but my gut says A
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What is the ratio of the areas of the signals in the h nmr spectrum of pentan-3-ol?
Damm [24]

The ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

<h3>What is a NMR spectrum?</h3>

Nuclear magnetic resonance spectroscopy is a spectroscopy that shows the detailed structure and chemical environment of a chemical element.

Pentan-3-ol contain 12 hydrogen atoms. In H-NMR spectra, hydrogen atoms have same environment gives a signal.

There are 4 different kinds of signals due of the 4 different environment experienced by these 12 hydrogens.

Thus, the  ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

Learn more about NMR spectrum

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8 0
2 years ago
What is the IUPAC name of the following compounds i. CO₂ ii. NO₂ iii. HNO3 iv. H₂SO4 v. K-Cr₂O vi. [Fe(CN)
Zielflug [23.3K]

Explanation:

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ii) nitrogen dioxide

iii) nitric acid

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8 0
2 years ago
A gas has a volume of 590 mL at temperature of -55.0 C. What volume will the gas occupy at 30.0 C show your work
DENIUS [597]
Data:
V_{initial} = 590\:mL
T_{initial} = -55.0^0C
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → T_{initial} = 218.0\:K
V_{final} = ? (in\:milliliters)
T_{final} = 30.0^0C
TK = TC + 273
TK = 30.0 + 273 → TK = 303.0 → T_{final} = 303.0\:K

By the first Law of Charles and Gay-Lussac, we have: 
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }

Solving:
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }
\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }
Product of extremes equals product of means:
218.0* V_{f} = 590*303.0
218.0 V_{f} = 178770
V_{f} = \frac{178770}{218.0}
\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark
7 0
3 years ago
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