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3 years ago

Find the mass percentage of water in ZnSO4 · 7H20 PLEASE HELP

Chemistry

1 answer:

netineya [11]3 years ago

8 0

Answer:

Hello, I can help!

Explanation:

Molecular Formula: ZnSO4. 7H2O or H14O11SZn

Molecular Weight: 287.6 g/mol

<h2>Computing molar mass (molar weight)</h2>

Functional groups: D, Ph, Me, Et, Bu, AcAc, For, Ts, Tos, Bz, TMS, tBu, Bzl, Bn, Dmg

Common compound names.

Examples of molar mass computations: NaCl, Ca(OH)2, K4[Fe(CN)6], CuSO4*5H2O, water, nitric acid, potassium permanganate, ethanol, fructose.

-Molecular mass (molecular weight) is the mass of one molecule of a substance and is expressed in the unified atomic mass units (u). (1 u is equal to 1/12 the mass of one atom of carbon-12)

-Molar mass (molar weight) is the mass of one mole of a substance and is expressed in g/mol.

God bless you!

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Two perfumes are released at the same time. If one is standing 7.5 m from the point of release. Perfume A (molar mass 275 g/mol)

natta225 [31]

According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".

rᵇ/rᵃ =   $\sqrt{da/db}$
Or,
  rᵇ/rᵃ =   $\sqrt{Ma/Mb}$ ----- (1)
As,
Ma = 275 g/mol

Mb = 205 g/mol

Putting Values in eq.1,

rᵇ/rᵃ =   $\sqrt{275/205}$

rᵇ/rᵃ = 1.15

Result:
Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.

6 0

2 years ago

Give the effect on the melting point of the presence of a cis double bond in a fatty acid.

vovikov84 [41]

Answer:

The cis double bond present in unsaturated fatty acids acids results in lower melting point when compared to saturated fatty acids of the same chain length.

Explanation:

Melting point of a fatty acids are affected by the length and degree of unsaturation of the hydrocarbon chain.

At room temperature, saturated fatty acids with hydrocarbon chain lengths between 12-24 are waxy solids whereas unsaturated atty acids of the same chain length are liquids. This is due to the nature of the packing of the fatty acid molecules in the saturated and unsaturated compounds.

In the saturated compounds, the molecules are tightly packed side by side with minimal steric hindrance and maximal van der Waals forces of attraction between molecules. However, in unsaturated fatty acids, the cis double bond introduces a bend or kink in the molecules which then interferes with the tight packing of the molecules and reducing interaction between molecules. Therefore, less energy is required to cause a disorder in the arrangement of unsaturated fatty acids, leading to a lowering of melting point.

8 0

2 years ago

Calculate the mass, in grams, of 1.2000 mol Mg₃N₂

fredd [130]

So what do you want me to do
Explanation

7 0

2 years ago

Find the total number of moles of ions produced when 0.347 mol of sodium carbonate dissolves.

Ahat [919]

Answer:

molarity= 0.238 mol L-

Explanation:

The idea here is that you need to use the fact that all the moles of sodium phosphate that you dissolve to make this solution will dissociate to produce sodium cations to calculate the concentration of the sodium cations.

Na 3 PO 4 (aq) → Na + (aq) + PO3−4 (aq)

Use the molar mass of sodium phosphate to calculate the number of moles of salt used to make this solution.

3.25g⋅1 mole N 3PO4 163.9g = 0.01983 moles Na3 PO 4

Now, notice that every

1 mole of sodium phosphate that you dissolve in water dissociates to produce

3bmoles of sodium cations in aqueous solution.

4 0

2 years ago

A 0.105 L sample of an unknown HNO 3 solution required 35.7 mL of 0.250 M Ba ( OH ) 2 for complete neutralization. What is the c

oksano4ka [1.4K]

Answer: 0.17M

Explanation:

The equation for the reaction is :

2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O

From the balanced equation, we obtain :

nA = mole of acid = 2

nB = mole of the base = 1

From the question, we obtain:

Va = Vol. Of acid = 0.105L

Ma = conc. Of acid =?

Vb = Vol of base = 35.7 mL = 0.0357L

Mb = conc. of base = 0.25M.

We solve for the conc. of the acid using:

MaVa / Mb Vb = nA / nB

(Ma x 0.105) / (0.25x0.0357) = 2

Cross multiply to express in linear form. We have:

Ma x 0.105 = 0.25 x 0.0357 x 2

Divide both side by 0.105. We have

Ma = (0.25 x 0.0357 x 2) / 0.105

Ma = 0.17M

Therefore the concentration of the acid(HNO3) is 0.17M

3 0

2 years ago