Question

Find the equation of the circle that passes through the point (-3,1) and has its center at C(-4,6)

Answer 1

Answer:

(x+4)^2 + (y-6)^2 = 29

Step-by-step explanation:

The center-radius form of the circle equation is in the format (x – h)^2 + (y – k)^2 = r^2, with the center being at the point (h, k)

Replacing the center C(-4,6):

(x+4)^2 + (y-6)^2 = r^2

then replacing the point (-3,1):

(-3+4)^2 + (1-6)^2 = r^2

1 + 25 = r^2

then the equation of the circle is:

(x+4)^2 + (y-6)^2 = 29