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atroni [7]
4 years ago
8

Based only on the given information, it is guaranteed that AD = DB

Mathematics
1 answer:
Law Incorporation [45]4 years ago
5 0

Answer: True

Step-by-step explanation:

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Find ordered pairs: choose two of the answers below
Anarel [89]

Answer:

b -3,3 c 6,9 hope this helps

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3 years ago
The elevation of city a is 80 feet below sea level, the elevation of city c is 16 feet below sea level. The elevation of city D
tekilochka [14]
I am almost positive that the answer could be 8 feet below sea level
6 0
3 years ago
Jenny gave her brother 4 stickers what fraction does she have left
coldgirl [10]
1/4 or 4/8 or 5/10

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4 0
3 years ago
Read 2 more answers
Multiply.
Crank
The main rules that we use here are :

i) \sqrt{a \cdot b}=  \sqrt{a} \cdot \sqrt{b} for nonnegative values a and b.

ii) \sqrt{a} \cdot  \sqrt{a} =a.


Thus, first 'decompose' the numbers in the radicals into prime factors:

4 \sqrt{3} \cdot 10 \cdot  \sqrt{2\cdot2\cdot3}\cdot  \sqrt{2\cdot 3}\cdot  \sqrt{2}..

By rule (i) we write:

4 \sqrt{3} \cdot 10 \cdot \sqrt{2}\cdot \sqrt{2}\cdot \sqrt{\cdot3}\cdot \sqrt{2} \cdot  \sqrt{3} \cdot \sqrt{2}.

We can collect these terms as follows:

40 \sqrt{3}\cdot (\sqrt{3}\cdot \sqrt{3}) \cdot (\sqrt{2}\cdot \sqrt{2}) \cdot( \sqrt{2} \cdot \sqrt{2}), and by rule (ii) we have:

40 \sqrt{3}\cdot 3 \cdot 2 \cdot2=40\cdot12\cdot \sqrt{3}=480 \sqrt{3}.


Answer: 480 \sqrt{3}.
8 0
4 years ago
A pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. The height, h, of th
Gennadij [26K]
<h2>Explanation:</h2>

In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:

h(t) = -16t^2 + 84t + 20

So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:

\text{The x-value of the vertex is}: \\ \\ t=-\frac{b}{2a} \\ \\ \\ Where: \\ \\ a=-16 \\ \\ b=84 \\ \\ c=20 \\ \\ \\ t=-\frac{84}{2(-16)} \\ \\ t=-\frac{84}{-32} \\ \\ t=\frac{21}{8}=2.625 \\ \\ h(2.625)=-16(2.625)^2+84(2.625)+20 \\ \\ h(2.625)=-110.25+220.5+20 \\ \\ h(2.625)=130.25m

Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m

8 0
3 years ago
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