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3 years ago

Why doesn't potassium fluoride conduct electricity as a solid?

1 answer:

5 0

potassium flouride is an ionic compound and ionic compounds do not conduct electricity in solid form instead it conducts electricity in molten state.Ionic compounds do not conduct electricity in solid state because their ions are fixed while in molten form the ions are free

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Barium-142 is used as a GI radiocontrast agent. After 1.25 hours, 9.25 μg remains in the patient. Determine the original dose gi

Trava [24]

Answer:

The answer to your question is the original dose of Ba-142 was 1184 μg

Explanation:

Data

Total time = 1.25 hours

The Final amount of Ba = 9.25 μg

The Half-life of Ba = 10.6 minutes

Process

1.- Convert total time to minutes

1 h ----------------- 60 min

1.25 h ------------ x

x = 75 min

2.- Draw a table of this process

Final amount of Ba Time

9.25 75 min

18.5 64.4 min

37 53.8 min

74 43.2 min

148 32.6 min

296 22 min

592 11.4 min

1184 0.8 min

4 0

3 years ago

Generally the periodic trends of the d and f block is similar to the main group elements trends.

exis [7]

Answer:

False

Explanation:

7 0

3 years ago

For every 0.50 moles of CaC2O4 formed, how many moles of NaI are Formed?

fiasKO [112]

Answer:

1.45 moles of Na2O produced

Explanation:

mark as brainiest

3 0

2 years ago

Solid aluminum and gaseous oxygen react in a combination reaction to produce aluminum oxide: 4Al (s) + 3O2 (g) â†’ 2Al2O3 (s) In

jek_recluse [69]

Answer: The percent yield of the reaction is 74 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

$\text{Moles of aluminium}=\frac{2.5g}{27g/mol}=0.092mol$

For oxygen gas:

$\text{Moles of oxygen gas}=\frac{2.5g}{32g/mol}=0.078mol$

The chemical equation for the reaction of titanium and chlorine gas follows:

$4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)$

By Stoichiometry of the reaction:

4 moles of aluminium reacts with 3 moles of oxygen.

So, 0.092 moles of aluminium reacts with = $\frac{3}{4}\times 0.092=0.069mol$ of oxygen

As, given amount of oxygen is more than the required amount. So, it is considered as an excess reagent.

Thus, aluminium is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of aluminium produce = 2 moles of $Al_2O_3$

So, 0.092 moles of aluminium will produce = $\frac{2}{4}\times 0.092=0.046moles$ of $Al_2O_3$

Now, calculating the mass of aluminium oxide:

$\text{Mass of aluminium oxide}=moles\times {\text {molar mas}}=0.046mol\times 102g/mol=4.7g$

To calculate the percentage yield of titanium (IV) chloride, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield = 3.5 g

Theoretical yield = 4.7 g

Putting values in above equation, we get:

$\%\text{ yield of reaction}=\frac{3.5g}{4.7g}\times 100\\\\\% \text{yield of reaction}=74\%$

Hence, the percent yield of the reaction is 74 %

6 0

3 years ago

What is 50 plus 50vhvvhygygyfyftftfffffffrdrdrdrdrdr?

jeka94

The answer would b 100<span>vhvvhygygyfyftftfffffffrdrdrdrdrdr</span>

5 0

4 years ago

Read 2 more answers