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Llana [10]
3 years ago
14

The Electrical conductivity of an aqueous solution depends on the concentration of which particles in the solution

Chemistry
2 answers:
Kazeer [188]3 years ago
7 0

Answer: Option (4) is the correct answer.

Explanation:

When a solution contains number of ions then this type of solution is able to conduct electricity.

For example, when NaCl is dissolved in water the NaCl dissociates into Na^{+} and Cl^{-} ions. Hence, flow of these ions will be responsible for electrical conductivity.

Whereas flow of electrons in a conductor is responsible for electrical conductivity but in a solution ions are responsible for the flow of electrical current.

Thus, we can conclude that the electrical conductivity of an aqueous solution depends on the concentration of which particles in the solution ions.

anyanavicka [17]3 years ago
6 0
It depends on the concentration of ions which are responsible for the electrical conductivity in aqueous solutions.
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A student made a graph to show the chemical equilibrium position of a reaction.
pogonyaev

Answer:

Concentration, because the amounts of reactants and products remain constant after equilibrium is reached.

Explanation:

The rate of reaction refers to the amount of reactants converted or products formed per unit time.

As the reaction progresses, reactions are converted into products. This continues until equilibrium is attained in a closed system.

When equilibrium is attained, the rate of forward reaction is equal to the rate of reverse reaction, hence the concentration of reactants and products in the system remain fairly constant over time.

When deducing the rate of reaction, concentration of the specie of interest is plotted on the y-axis against time on the x-axis.

8 0
3 years ago
Last time I'm asking this, answer, this time, 50 points.
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Explanation:

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6 0
2 years ago
In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to
labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of NH_3 = 100 g

Molar mass of NH_3 = 27 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate moles of NH_3.

\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles

The given balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the given reaction, we conclude that

2 moles of NH_3 produced from 1 mole of N_2

3.7 moles of NH_3 produced from \frac{1mole}{2mole}\times 3.7mole=1.85moles of N_2

Now we have to calculate the mass of N_2.

Mass of N_2 = Moles of N_2 × Molar mass of N_2

Mass of N_2 = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0
3 years ago
Need help ASAP please!
bearhunter [10]

Answer:

13 mol NO

Explanation:

Step 1: Write the balanced equation

4 NH₃(g) + 5 O₂(g) ⇒ 4 NO(g) + 6 H₂O(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to NO is 5:4.

Step 3: Calculate the number of moles of O₂ needed to produce 16 moles of NO

We will use the previously established molar ratio.

16 mol O₂ × 4 mol NO/5 mol O₂ = 13 mol NO

3 0
3 years ago
What observations can you make about this group of people? Name one inference you can make from your observations.​
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3 years ago
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