What is the mass of 0.5 moles of carbon tetrafluoride, CF4?
2 answers:
Answer:
44 g
Explanation:
The formula for the number of moles (n) is equal to .
Since we need to find the mass, we derive it from the formula of the number of moles and we get that mass = n x molecular weight .
The molecular weight of = 12 g/mol (from the carbon) + 19x4 g/mol (from the 4 fluorine atoms)= 88 g/mol
We plug in the numbers in the derived formula for the mass and we get :
mass = n x molecular weight = 0.5 mol x 88 g/mol = 44 g
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The empirical formula for a compound composed of 0.0683 mol of carbon ( C ), 0.0341 mol of hydrogen ( H ), and 0.1024 mol of nitrogen ( N ) is .
An empirical formula tells us the relative ratios of different atoms in a compound.
Given data:
Moles of carbon = 0.0683 mol
Moles of hydrogen = 0.0341 mol
Moles of nitrogen = 0.1024 mol
Dividing each mole using the smallest number that is divided by 0.0341 moles.
We get:
Carbon= 2
Hydrogen=1
Nitrogen=3
The empirical formula for a compound is.
Learn more about empirical formula here:
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