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olga55 [171]
3 years ago
12

What is the mass of 0.5 moles of carbon tetrafluoride, CF4?

Chemistry
2 answers:
klasskru [66]3 years ago
7 0

Answer:

44.0015

Explanation:

we go and look at the mass for carbon which is 12.011 then at the mass of fluorine which is 18.998. Since there are 4 Fluorines the we multiply 4 by 18.998 which we get 75.992. Then we add 75.992 + 12.011 which will give us 88.003 then multiply 88.003 by 0.5 which gives us 44.0015

VashaNatasha [74]3 years ago
4 0

Answer:

44 g

Explanation:

The formula for the number of moles (n) is equal to n=\frac{mass}{molecular weight} .

Since we need to find the mass, we derive it from the formula of the number of moles and we get that mass = n x molecular weight .

The molecular weight of CF_{4} = 12 g/mol (from the carbon) + 19x4 g/mol (from the 4 fluorine atoms)= 88 g/mol

We plug in the numbers in the derived formula for the mass and we get :

mass = n x molecular weight = 0.5 mol x 88 g/mol = 44 g

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How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?
Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

C_{6}H_{8}O_{6}

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g

To know the percent of each element, we need to to the following:

C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0
3 years ago
During the formation of a chemical bond between two hydrogen atoms, which of the following statements is always true?
Wewaii [24]

A) Energy is released during the formation of the bond.

Explanation:

During the formation of a chemical bonds between two hydrogen atoms, energy is always released during the formation of this bond type.

Bond formation process is usually exothermic and energy is released during the formation of the bond.

  • Bond breaking process is an endothermic process in which energy is absorbed from the surrounding.
  • Whenever a bond is broken, the bond energy value is positive but when a bond is formed, the bond energy value is given a negative sign.

For a bond formation process in which hydrogen atoms are bonded covalently, energy is usually released.

Learn more:

Enthalpy changes brainly.com/question/10567109

#learnwithBrainly

5 0
3 years ago
What kind of chemical bond is formed between nonmetals? Explain your answer.
REY [17]

Answer:

The ionic bond is formed due to an electrostatic force of attraction between two oppositely charged ions. This bond is usually formed between a metal and a nonmetal. Prior to the electrostatic attraction, there is a total transfer of valence electrons from one atom to the other atom.

Explanation: hope that helps

5 0
3 years ago
How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0
2 years ago
1-The chemical potential energy of bond A is greater than the chemical potential energy of bond B. Which statement best explains
Tju [1.3M]

It should be noted that bond A has greater energy because C. The atoms in bond A are held more tightly together than the atoms in bond B.

<h3>Bond</h3>

The relationship between the bond energies of nitrogen, iodine, and fluorine gases is that the bond in nitrogen gas is the most difficult to break.

From the information given, the molecule with the greatest bid energy is CH4. The bind energy measures the bond strength that the chemical bond has.

Also, the bond energy of the reactants in reaction 1 is greater than the bond energy of the reactants in reaction 2. Due to this, reaction 1 requires a greater input of energy than reaction 2.

Lastly, the difference in the bond energy of Chlorine and Bromine is that Bromine has more electron levels than chlorine.

Learn more about bonds on:

brainly.com/question/819068

6 0
3 years ago
Read 2 more answers
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