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olga55 [171]
3 years ago
12

What is the mass of 0.5 moles of carbon tetrafluoride, CF4?

Chemistry
2 answers:
klasskru [66]3 years ago
7 0

Answer:

44.0015

Explanation:

we go and look at the mass for carbon which is 12.011 then at the mass of fluorine which is 18.998. Since there are 4 Fluorines the we multiply 4 by 18.998 which we get 75.992. Then we add 75.992 + 12.011 which will give us 88.003 then multiply 88.003 by 0.5 which gives us 44.0015

VashaNatasha [74]3 years ago
4 0

Answer:

44 g

Explanation:

The formula for the number of moles (n) is equal to n=\frac{mass}{molecular weight} .

Since we need to find the mass, we derive it from the formula of the number of moles and we get that mass = n x molecular weight .

The molecular weight of CF_{4} = 12 g/mol (from the carbon) + 19x4 g/mol (from the 4 fluorine atoms)= 88 g/mol

We plug in the numbers in the derived formula for the mass and we get :

mass = n x molecular weight = 0.5 mol x 88 g/mol = 44 g

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Considering the Boyle's law, the new pressure of the sample is 1,776 mmHg.

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Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

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Boyle's law is expressed mathematically as:

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Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following will be true:

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In this case, you know:

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The empirical formula for a compound composed of 0.0683 mol of carbon ( C ), 0.0341 mol of hydrogen ( H ), and 0.1024 mol of nitrogen ( N ) is  C_2HN_3.

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An empirical formula tells us the relative ratios of different atoms in a compound.

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