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2 years ago

What is the mass of 0.5 moles of carbon tetrafluoride, CF4?

Chemistry

2 answers:

klasskru [66]2 years ago

7 0

Answer:

44.0015

Explanation:

we go and look at the mass for carbon which is 12.011 then at the mass of fluorine which is 18.998. Since there are 4 Fluorines the we multiply 4 by 18.998 which we get 75.992. Then we add 75.992 + 12.011 which will give us 88.003 then multiply 88.003 by 0.5 which gives us 44.0015

VashaNatasha [74]2 years ago

4 0

Answer:

44 g

Explanation:

The formula for the number of moles (n) is equal to $n=\frac{mass}{molecular weight}$ .

Since we need to find the mass, we derive it from the formula of the number of moles and we get that mass = n x molecular weight .

The molecular weight of $CF_{4}$ = 12 g/mol (from the carbon) + 19x4 g/mol (from the 4 fluorine atoms)= 88 g/mol

We plug in the numbers in the derived formula for the mass and we get :

mass = n x molecular weight = 0.5 mol x 88 g/mol = 44 g

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Which of the following happens to a molecule of an object when the object is heated? (1 point)

vfiekz [6]

Answer:

They get more energy, so they vibrate!

Explanation:

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2 years ago

Hereditary information is stored inside the

Julli [10]

Answer:Hereditary information is contained in genes, located in the chromosomes of each cell. Each gene carries a single unit of information. An inherited trait of an individual can be determined by one or many genes, and a single gene can influence more than one trait.

Explanation:

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1 year ago

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

Given:

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

To determine:

The mean free path, λ

Calculation:

The mean free path is related to the collision cross section by the following equation:

$\lambda =\frac{1}{n\sigma }------(1)$

where n = number density

$n = \frac{P}{kT}-----(2)$

Substituting for P, k and T in equation (2) gives:

$n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\ m^{3}$

Next, substituting for n and σ in equation (1) gives:

$\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m$

6 0

2 years ago

An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $7200 and his st

djyliett [7]

Answer:

22.7%

Explanation:

Given that last year stock for company A was $7200

The stock for company B last year was worth $3510

Stock in company A decreased by 24%

This means the new value of stock for company A became;

(100-24)/100 *$7200

76/100*$7200

0.76*7200 =$5472

Stock in company B decreased by 20%

This means the new value of stock for company B became;

(100-20)/100 *$3510

80/100*$3510

0.8*$3510

$2808

Original investors stock value was = $7200+$3510 =$10710

New investors stock value is = $5472+$2808=$8280

Decrease in value of stock = $10710-$8280 =$2430

percentage decrease in stock value = decrease in stock/original value of stock *100%

=2430/10710 *100 =22.689

=22.7%

7 0

2 years ago

Cu20(s) + C(s) - 2Cu(s) + CO(g)

Romashka-Z-Leto [24]

Answer:

That means Cu2O is limiting reagent and C is excess reagent

Explanation:

Based on the reaction, 1 mole of Cu2O reacts per mole of C. The ratio of reaction is 1:1.

To solve this question we need to convert the mass of each reactant to moles. The reactant with the lower amount of moles is limiting reactant and the excess reactant is the reactant with the higher number of moles.

Moles Cu2O -Molar mass: 143.09 g/mol-

114.2g Cu2O * (1mol / 143.09g) = 0.798 moles Cu2O

Moles C -Molar mass: 12.01g/mol-

11.1g C * (1mol / 12.01g) = 0.924 moles C

<h3>That means Cu2O is limiting reagent and C is excess reagent</h3>

6 0

2 years ago