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jeyben [28]
1 year ago
10

Which chemical out of the following 4 is the most dangerous? Glucose, benzene,acetone, ether

Chemistry
1 answer:
Lelechka [254]1 year ago
5 0

Answer:

B.

Explanation: hope this helps

Benzene

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Calculate the percentage by mass of chlorine in Cobalt (II) chloride (cocl2)​
Likurg_2 [28]

Explanation:

Divide the mass of chlorine by the molar mass of cobalt chloride, then multiply by 100.

Molar Mass of Cobalt Chloride.

Mass of Chlorine in Cobalt Chloride.

Percent Composition of Chlorine.

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3 years ago
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Explain why chemical equations have to be balanced
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Chemical equations are to be balanced to be able to follow the law of conservation of mass where it says that mass cannot be created or destroyed. Reactions should be that the mass of the reactants is equal to the mass of the products. 
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2Fe(OH)3 Fe2O3+3H2O how many grams of Fe2O3 are produced if 10.7 grams of Fe (OH)3 react in this way
sasho [114]

Answer: 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)  

Putting values in equation 1, we get:

\text{Moles of} Fe(OH)_3=\frac{10.7g}{106.87g/mol}=0.100mol  

The chemical equation for the reaction is

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O

By Stoichiometry of the reaction:

2 moles of Fe(OH)_3 produce = 1 mole of Fe_2O_3

So, 0.100 moles of Fe(OH)_3 produce= \frac{1}{2}\times 0.100=0.05mol of Fe_2O_3  

Mass of Fe_2O_3 =moles\times {\text{Molar Mass}}=0.05mol\times 159.69g/mol=7.98g  

Hence 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

3 0
2 years ago
If 48 g of magnesium reacts with oxygen gas, how many grams of magnesium oxide will be formed according to the following equatio
Aloiza [94]

think it maybe 48 mg0 because there should be 2g magnesium in the word equation

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2 years ago
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Help please! please answer with a good answer ​
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Answer:

what the heck what is that?

Explanation:

5 0
3 years ago
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