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xenn [34]
3 years ago
12

If mâ 4 = (3x)° and mâ 8 = (x + 40)°, what is the measure of â 4? â 4 and â 8 are vertical.

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0
X*Y+4326-74*H=7000
,,,,,,

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Help geometry ………ignore this i need 20 words
Anarel [89]

Answer:

The answer is 1

Step-by-step explanation:

5 0
2 years ago
No link answers please!!
nignag [31]

Answer: X= 6 or X=-4

Step-by-step explanation:

x^{2} -2x-24=0\\(x-6)(x+4)=0\\x-6=0 --> x=6\\x+4=---> x=-4

8 0
3 years ago
Type your answer and then click or tap Done.
masya89 [10]

Answer:

See below

Step-by-step explanation:

x(x-2y)-(y-x)2  

Final result :

-y2

Step by step solution :

Step  1  :

Equation at the end of step  1  :

x • (x - 2y) -  (y - x)2

Step  2  :

2.1     Evaluate :  (y-x)2   =    y2-2xy+x2  

Final result :

-y2

7 0
2 years ago
Divide f(x) by d(x), and write a summary statement in the form indicated.
lukranit [14]
( x^4 - 4 x³ + 2 x² - 4 x + 1 ) : ( x² + 1 )   =  x² - 4 x + 1
- x^4             - x²
------------------------
          - 4 x³ + x² - 4 x
            4 x³        + 4 x
         -----------------------
                      x²  + 1
                   - x²   - 1
                ----------------
                   R ( x ) = 0
( x^4 - 4 x³ + 2 x² - 4 x + 1) =  ( x² + 1 ) ( x² - 4 x + 1 )
3 0
3 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
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