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Reptile [31]
3 years ago
11

On reaction with acidified potassium dichromate(VII), two of the isomers are oxidized in two steps to produce different products

. Draw the structural formula of the two products formed from one of the isomers.

Chemistry
1 answer:
ohaa [14]3 years ago
3 0

Answer:

First, you don't specify which are the isomers to be oxidized. So I will show you some examples.

Explanation:

Oxidizing the different types of alcohols

The oxidizing agent used in these reactions is normally a solution of sodium or potassium dichromate(VI) acidified with dilute sulfuric acid. If oxidation occurs, then the orange solution containing the dichromate(VI) ions is reduced to a green solution containing chromium(III) ions. The electron-half-equation for this reaction is as follows:

Cr2O2−7 + 14H+ + 6e− → 2Cr3+ + 7H2O (1)

Primary alcohols

Primary alcohols can be oxidized to either aldehydes or carboxylic acids, depending on the reaction conditions. In the case of the formation of carboxylic acids, the alcohol is first oxidized to an aldehyde, which is then oxidized further to the acid.

An aldehyde is obtained if an excess amount of the alcohol is used, and the aldehyde is distilled off as soon as it forms. An excess of the alcohol means that there is not enough oxidizing agent present to carry out the second stage, and removing the aldehyde as soon as it is formed means that it is not present to be oxidized anyway!

If you used ethanol as a typical primary alcohol, you would produce the aldehyde ethanal,  CH3CHO . The full equation for this reaction is fairly complicated, and you need to understand the electron-half-equations in order to work it out.

3CH3CH2OH + Cr2O2−7 + 8H+ → 3CH3CHO + 2Cr3+ + 7H2O

(See image 1 and 2)

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32 gm of O2 to mole of O2
lana [24]

Molar mass of O2:-

\\ \rm\longmapsto 2(16u)=32g/mol

Now

\boxed{\sf No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \rm\longmapsto No\:of\;moles=\dfrac{32}{32}

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5 0
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What is the charge of oxygen in Na2O?
Nuetrik [128]

In Na2O, what is the oxidation state of oxygen? In Na2O oxidation state of Na is 1+
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The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
gladu [14]
Hbro  dissociate  as  follows
HBro--->  H+  +  BrO-
  Ka=  (H+)(BrO-)  /  HBro
 PH  =  -log (H+)
therefore (H+)  =  10^-4.48= 3.31  x10^-5
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6 0
3 years ago
W
DerKrebs [107]

Answer:

F = 30 N

Explanation:

Given data:

Mass of toy train = 1.5 kg

Acceleration of train = 20 m/s²

Amount of force acting on it = ?

Solution:

The net force on object is equal to the its mass multiply by its acceleration.

Formula:

F = ma

F = force

m = mass

a = acceleration

Now we will put the values in formula.

F = 1.5 kg × 20ms⁻²

F = 30 kg.ms⁻²

kg.ms⁻² = N

F = 30 N

7 0
3 years ago
How many moles of sodium carbonate na2co3 are contained by 57.3 g of sodium carbonate
yan [13]
There are 0.54 moles of sodium carbonate are contained by  57.3 grams of sodium carbonate.

we can calculate number of moles in a compound by dividing number of grams of compound by the molar mass of the compound.
molar mass of sodium carbonate = 105.987 g/mol
now, 57.3 / 105.987 = 0.54 moles
6 0
3 years ago
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