Answer:
The charge is +2
Explanation:
Protons are positive, electrons are negative. 10-8=2.
+2 :)
<span> ester of Ethanol and Ethanoic Acid is Ethyl Ethanoate. </span>
<span><span><span><span><span><span><span><span>C</span></span></span><span><span><span>2</span></span></span></span><span><span><span><span>H</span></span></span><span><span><span>5</span></span></span></span><span><span>O</span></span><span><span>H</span></span><span><span>(</span></span><span><span>l</span></span><span><span>)</span></span><span><span>+</span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>3</span></span></span></span><span><span>C</span></span><span><span>O</span></span><span><span>O</span></span><span><span>H</span></span><span><span>(</span></span><span><span>l</span></span><span><span>)</span></span><span><span><span><span><span><span><span><span><span>c</span></span><span><span>o</span></span><span><span>n</span></span><span><span>c</span></span><span><span>.</span></span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>S</span></span><span><span><span><span>O</span></span></span><span><span><span>4</span></span></span></span><span><span><span><span>/</span></span></span></span><span><span>w</span></span><span><span>a</span></span><span><span>r</span></span><span><span>m</span></span></span></span><span /></span></span></span><span><span><span><span>−</span><span>−−−−−−−−−−</span><span>→</span></span></span></span></span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>3</span></span></span></span><span><span>C</span></span><span><span>O</span></span><span><span>O</span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>3</span></span></span></span><span><span>(</span></span><span><span>a</span></span><span><span>q</span></span><span><span>)</span></span><span><span>+</span></span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>O</span></span><span><span>(</span></span><span><span>l</span></span><span><span>)</span></span></span></span><span>C2H5OH(l)+CH3COOH(l)→conc.H2SO4/warmCH3COOCH2CH3(aq)+H2O(l)</span></span></span>
<span><span><span><span><span><span>Condition: Warm con. reactants with conc.</span></span></span></span><span>Condition: Warm con. reactants with conc.</span></span></span><span><span><span><span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>S</span></span><span><span><span><span>O</span></span></span><span><span><span>4</span></span></span></span></span></span><span>H2SO4</span></span></span>
Answer is (1) - no reaction.
<em>Explanation;
</em>
Some of you may think this reaction as a single replacement reaction which gives NaBr + F₂ as products.
But, according to the reactivity of the halogens, reactivity decreases from up to bottom of the group. F is placed above Br. Hence, F is more reactive than Br. Hence, Br can't replace F.
Answer:
geez I have no clue sorry
