All categories

3 years ago

What is the volume of an object with a mass of 11.5 g and a density of 1.3 g/mL?

Chemistry

1 answer:

Sliva [168]3 years ago

3 0

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass of object = 11.5 g

density = 1.3 g/mL

The volume is

$volume = \frac{11.5}{1.3} \\ = 8.846153$

We have the final answer as

Hope this helps you

You might be interested in

Consider the chemical equilibrium of the reaction. NH4OH(aq) mc014-1.jpg NH4+(aq) + OHmc014-2.jpg(aq) What will happen to the ch

Bingel [31]

The chemical equilibrium will shift to the left.
Since NH4+ ions are a product of the original reaction, increasing their concentration will shift the equilibrium toward the reactants.

8 0

2 years ago

Read 2 more answers

Hypothesis for does water with salt boil faster than plain water

Ronch [10]

If you add salt to water then it will boil faster than water without salt

3 0

3 years ago

Read 2 more answers

Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9

EleoNora [17]

Answer : The current passing between the electrodes is, $1.056\times 10^{-2}A$

Explanation :

First we have to calculate the charge of sodium ion.

$q=ne$

where,

q = charge of sodium ion

n = number of sodium ion = $2.68\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C$

Now we have to calculate the charge of chlorine ion.

$q'=ne$

where,

q' = charge of chlorine ion

n = number of chlorine ion = $3.92\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C$

Now we have to calculate the current passing between the electrodes.

$I=\frac{q}{t}+\frac{q'}{t}$

$I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}$

$I=1.056\times 10^{-2}A$

Thus, the current passing between the electrodes is, $1.056\times 10^{-2}A$

4 0

2 years ago

The chemical equation is Mg(s) + O2(g) → MgO(s)

vredina [299]

Answer:

The magnesium will burn until consumed entirely. There is much more oxygen available in the atmosphere than needed to consume the magnesium. Thus the magnesium is the limiting reactant because it determines the amount of product formed.

Explanation:

Mg produces less amount of MgO than O2; therefore Mg is the limiting reagent. O2 produces more amount of MgO than Mg; therefore O2 is the excess reagent.

4 0

2 years ago

Scientific explanations

Sergio039 [100]

I think that it's cannot include supernatural explanations, or C.

If i got it wrong sorry

6 0

3 years ago