All categories

2 years ago

What is the volume of an object with a mass of 11.5 g and a density of 1.3 g/mL?

Chemistry

1 answer:

Sliva [168]2 years ago

3 0

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass of object = 11.5 g

density = 1.3 g/mL

The volume is

$volume = \frac{11.5}{1.3} \\ = 8.846153$

We have the final answer as

Hope this helps you

You might be interested in

1. What trends do you see when considering total electrons, valence electrons (highest occupied energy level/outermost level ele

NNADVOKAT [17]

ELECTRON CONFIGURATION

Highest occupied energy level of an element

equal to the period
for example, the highest occupied energy level of He is 1, Be is 2, Al is 3, Ca is 4, and Sn is 5

6 0

2 years ago

Read 2 more answers

Please help this is due today

PilotLPTM [1.2K]

A. Solid Liquid Gas

8 0

2 years ago

In reality, a hydrate of iron(III) nitrate had to be used, not the anhydrous salt. As you may guess, some of the hydrate’s mass

liq [111]

<u>Answer:</u> The mass of nonahydrate iron (III) nitrate is 16.2 g

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of $Fe(NO_3)_3$ = 0.0020 M

Volume of solution = 2 L

Putting values in above equation, we get:

$0.0200M=\frac{\text{Moles of }Fe(NO_3)_3}{2L}\\\\\text{Moles of }Fe(NO_3)_3=(0.0200mol/L\times 2L)=0.04mol$

The chemical equation for the decomposition of hydrated iron (III) nitrate follows:

$Fe(NO_3)_3.9H_2O\rightarrow Fe(NO_3)_3+9H_2O$

By Stoichiometry of the reaction:

1 mole of iron (III) nitrate is produced from 1 mole of hydrated iron (III) nitrate

So, 0.04 moles of iron (III) nitrate will be produced from = $\frac{1}{1}\times 0.04=0.04mol$ of hydrated iron (III) nitrate

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of nonahydrate iron (III) nitrate = 404.0 g/mol

Moles of nonahydrate iron (III) nitrate = 0.04 moles

Putting values in above equation, we get:

$0.04mol=\frac{\text{Mass of nonahydrate iron (III) nitrate}}{404.0g/mol}\\\\\text{Mass of nonahydrate iron (III) nitrate}=(0.04mol\times 404.0g/mol)=16.2g$

Hence, the mass of nonahydrate iron (III) nitrate is 16.2 g

7 0

2 years ago

What is the relationship between pH, acidity, and H1 concentration ?

irina [24]

PH = - log [concentration of H+]

pH = - log [H+]

pH IS A MEAUSE OF ACIDITY AND BASIDITY OF A SUBSTANCE....

AS ACIDITY OF A SUBSTANCE DEPENDS ON THE IONISATION OF H+
THEREFORE IT IS A MEAUSE...

THE LOWER THE PH VALUE, THE MORE ACIDIC IS THE SUBSTANCE

6 0

2 years ago

The mass of an astronaut in space will be:

Romashka-Z-Leto [24]

Greater than on earth....f=Gm1m2/r2

7 0

3 years ago

Read 2 more answers