1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vinvika [58]
3 years ago
9

The average dosage of oxcarbazepine for an epileptic child between the ages of 4 and 16 is 9.00 mg per 1 kg of body weight (9.00

mg/kg). Calculate how many milliliters of oxcarbazepine a child who weighs 37.3 pounds should be prescribed considering the medication is served as a suspension of 60.0 mg/mL. Keep in mind that 1 pound is equivalent to 0.453 kilograms.
Chemistry
2 answers:
melamori03 [73]3 years ago
8 0
Convert the child weight (37.3 pounds) to kilograms

37.3 lb x 0.453 kg /1lb = "A kg"

multiply the dose (9.00mg/kg) by the weight of the child to find how much you need to give him

A kg * 9.00 mg/1kg = "B mg" 

calculate the mL of suspension dividing the "B mg" by the concentration of the suspension 60.0 mg/mL

B mg * 1mL/ 60.0 mg = C mL <span>oxcarbazepine</span>
vovikov84 [41]3 years ago
7 0

Answer:

2.53 milliliters of oxcarbazepine medication should be given to the child.

Explanation:

The average dosage of oxcarbazepine for an epileptic child = 9.00 mg/kg

Weight of the child = 37.3 pounds = 16.9 kg

(1 pound = 0.453 kilograms)

Dosage of oxcarbazepine for 16.9 kg child:

= 9.00 mg/kg\times 16.9 kg=152 mg

Prescribed medication is served as 60.0 mg/mL which means that 60.0 mg of dose is present in 1 mL of water solution.

Then 152 mg of dose will be present in:

\frac{1 mL}{60.0}\times 152=2.53 mL

2.53 milliliters of oxcarbazepine medication should be given to the child.

You might be interested in
POV: You buy a composite cup at the store. Explain the reason for your decision.
Len [333]

Answer:

i bought it cuz i need a cup?

Explanation:

7 0
3 years ago
Read 2 more answers
C10H12O4S(s) + O2(g)  CO2(g) + SO2(g) + H2O(g)
ale4655 [162]

Answer: The coefficient for O_2(g) is 12.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

C_{10}H_{12}O_4S(s)+12O_2(g)\rightarrow 10CO_2(g)+SO_2(g)+6H_2O

Thus in the reactants, there are 12 molecules of oxygen in balanced chemical equation. Thus the coefficient for O_2(g) is 12.

8 0
3 years ago
What is the systematic name of Mg(NO3)2?A) Manganese nitrite.B) Magnesium nitrite.C) Magnesium nitrate.D) Manganese nitrate.
olganol [36]
Mg is magnesium. NO3 is nitrate. This gives you magnesium nitrate as an answer.
6 0
3 years ago
During the process of diluting a solution, ________.
lana [24]
A kfjfjdnsndmxkkdnndndnd
4 0
3 years ago
How does water vapor get into the atmosphere?
Brums [2.3K]

Answer:

through the water cycle

Explanation:

6 0
4 years ago
Other questions:
  • which change in the temperature of the one gram sample of water would cause the greatest increase in average kinetic energy of i
    13·1 answer
  • An electron is on a -2.5 eV energy level. the electron is stuck by a 2.5 eV photon. What will most likely happen?
    12·1 answer
  • What is a ionic conmpound?
    11·2 answers
  • SOMEONE PLS HELP ITS FOR A TEST!!
    5·2 answers
  • PLEASE HELP WORTH 50 POINTS NO LINKS I WILL MARK CORRECT ANSWER BRAINLIEST!!! complete this punnet square, enter your answer in
    10·1 answer
  • (25points) Explain in your own words the difference between atomic mass and atomic number. Where can you find this information o
    9·2 answers
  • Which of the following substance is NOT matter? *
    9·1 answer
  • I dont feel like doing math in science HELPP
    15·2 answers
  • Who is the intended audience?​
    6·2 answers
  • Compare the atomic sizes of sodium and magnesium. Explain. ​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!