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Vinvika [58]
3 years ago
9

The average dosage of oxcarbazepine for an epileptic child between the ages of 4 and 16 is 9.00 mg per 1 kg of body weight (9.00

mg/kg). Calculate how many milliliters of oxcarbazepine a child who weighs 37.3 pounds should be prescribed considering the medication is served as a suspension of 60.0 mg/mL. Keep in mind that 1 pound is equivalent to 0.453 kilograms.
Chemistry
2 answers:
melamori03 [73]3 years ago
8 0
Convert the child weight (37.3 pounds) to kilograms

37.3 lb x 0.453 kg /1lb = "A kg"

multiply the dose (9.00mg/kg) by the weight of the child to find how much you need to give him

A kg * 9.00 mg/1kg = "B mg" 

calculate the mL of suspension dividing the "B mg" by the concentration of the suspension 60.0 mg/mL

B mg * 1mL/ 60.0 mg = C mL <span>oxcarbazepine</span>
vovikov84 [41]3 years ago
7 0

Answer:

2.53 milliliters of oxcarbazepine medication should be given to the child.

Explanation:

The average dosage of oxcarbazepine for an epileptic child = 9.00 mg/kg

Weight of the child = 37.3 pounds = 16.9 kg

(1 pound = 0.453 kilograms)

Dosage of oxcarbazepine for 16.9 kg child:

= 9.00 mg/kg\times 16.9 kg=152 mg

Prescribed medication is served as 60.0 mg/mL which means that 60.0 mg of dose is present in 1 mL of water solution.

Then 152 mg of dose will be present in:

\frac{1 mL}{60.0}\times 152=2.53 mL

2.53 milliliters of oxcarbazepine medication should be given to the child.

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explain why the hydrogen atoms in a hydrogen gas molecule form nonpolar covalent bonds but oxygen and hydrogen atoms in water mo
marishachu [46]

Answer:

Explanation:

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.  

The atom with larger electronegativity attract the electron pair more towards itself and becomes partial negative while the other atom becomes partial positive.

Non polar covalent bond:

It is the bond where both bonded atoms share the pair of electron equally.

For example:

Hydrogen gas (H₂) is non polar covalent compound because the electronegativity of both bonded atoms are same. No poles are created that's why this is non polar covalent compound.

Polar covalent bond:

It is the bond where both bonded atoms share the pair of electron unequally.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive and bond is polar.

7 0
3 years ago
Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).
muminat

Hello!

Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).

We have the following data:

m (mass) = ? 

n (number of moles) = 5.20 moles

MM (Molar mass of C6H12) ≈ 84.2 g/mol

Now, let's find the mass, knowing that:

n = \dfrac{m}{MM}

5.20\:\:\diagup\!\!\!\!\!\!\!mol = \dfrac{m}{84.2\:g/\diagup\!\!\!\!\!\!\!mol}

m = 5.20*84.2

\boxed{\boxed{m = 437.84\:g}}\end{array}}\qquad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

4 0
2 years ago
Read 2 more answers
Use the Gizmo to estimate the age of each of the objects below. For these questions, each second in the Gizmo represents 1,000 y
ziro4ka [17]

Answer:

Check the explanation

Explanation:

AT = A0 e(-T/H)

... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life, in units of T.

Substituting what we know, we get...

0.71 = (1) e(-T/5730)

Solve for T...

loge(0.71) = -T/5730

T = -loge(0.71)(5730)

T = 1962 (conservatively rounded, T = 2000)

similarly for all

for aboriginal charcoal

0.28 = (1) e(-T/5730)

Solve for T...

loge(0.28) = -T/5730

T = -loge(0.28)(5730)

T = 7294 (conservatively rounded, T = 7000)

for mayan headdress

0.89 = (1) e(-T/5730)

Solve for T...

loge(0.89) = -T/5730

T = -loge(0.89)(5730)

T = 667 (conservatively rounded, T = 700)

for neanderthal

0.05 = (1) e(-T/5730)

Solve for T...

loge(0.05) = -T/5730

T = -loge(0.05)(5730)

T = 17165 (conservatively rounded, T = 17000)

7 0
3 years ago
Se requieren preparar 1500 ml de una solución al 55% en masa de hidróxido de calcio, sabiendo que la densidad de dicha solución
Masja [62]

Respuesta:

968 g Ca(OH)₂

Explicación:

Paso 1: Calcular la masa de solución

Tenemos 1500 mL de una solución cuya densidad es 1.17 g/mL, es decir, 1 mL de solución tiene una masa de 1.17 g.

1500 mL × 1.17 g/mL = 1.76 × 10³ g

Paso 2: Calcular la masa de hidróxido de calcio en 1.76 × 10³ g de solución

La solución tiene una concentración de 55% en masa de hidróxido de calcio, es decir, cada 100 gramos de solución hay 55 gramos de hidróxido de calcio.

1.76 × 10³ g Solución × 55 g Ca(OH)₂/100 g Solución = 968 g Ca(OH)₂

6 0
2 years ago
Out of magnesium and Calcium which element is more reactive give reason​
SIZIF [17.4K]

Answer:

Calcium is more reactive.

Explanation:

It is higher in the reactivity series, and contains more energy levels.

5 0
2 years ago
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