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Oxana [17]
3 years ago
6

The community of a pond is made up of all the...

Chemistry
1 answer:
madam [21]3 years ago
3 0
The surrounding ecosystem in and around the water
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Salinity is a measure of which of the following in water?
Lemur [1.5K]
The answer is dissolved salts
8 0
3 years ago
Read 2 more answers
Which statement best describes the formula equation cl1(g) + 2kbr(aq) —> 2kcl(aq)+br2(i)
Zigmanuir [339]

Answer:

The chlorine gas and potassium bromide solution react to form liquid  bromine and potassium chloride solution.

Explanation:

Chemical equation:

Cl₂(g) + KBr (aq) → KCl (aq) + Br₂(l)

Balanced chemical equation:

Cl₂(g) + 2KBr (aq) → 2KCl (aq) + Br₂(l)

This equation showed that the chlorine gas and potassium bromide solution react to form liquid  bromine and potassium chloride solution.

Chlorine is more reactive than bromine it displace the bromine from potassium and form potassium chloride solution.

The given equation is balanced and completely hold the law of conservation of mass.

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

8 0
3 years ago
A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce
spin [16.1K]

Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

                                                                    = 84 \times 10^{3} kg

Flow rate of river is 50 m^{3} sec^{-1}

Volume of water in 1 day = 50 \times 10^{3} \times 86400 liter

                                          = 432 \times 10^{7} liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 2.9792 \times 10^{10} mg or 2.9792 \times 10^{4} kg

Flow rate of sewage = 0.7 m^{3} sec^{-1}

Volume of sewage water in 1 day = 6048 \times 10^{4} liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = 1.8144 \times 10^{10} mg or 1.8144 \times 10^{4}kg

Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

                                        = 6.8078 mg/l

                 k_{D} = 0.2 per day

       L_{o} = 6.8078

Hence, L_{liquid} = L_{o}(1 - e^{-k_{D}t}

             L_{liquid} = 6.8078 (1 - e^{-0.2 \times 1})  

                             = 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

                                                             = 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0
3 years ago
Find the density of a cube on Earth that weighs 1.5 kg and has a side-length of 10 cm.
Inga [223]

Answer:

1.5g/cm³

Explanation:

density=mass÷volume

mass= 1.5kg (<em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>o</em><em> </em><em>g</em>) = 1500g

volume of the cube = 10×10×10 = 1000cm³

density= divide 1500g÷1000cm = 1.5g/cm³

<h2>Density= 1.5g/cm³</h2>

YOUR WELCOME!

4 0
3 years ago
I'll mark brainliest!! :)
Viefleur [7K]
I believe the answer is C, AgBr. I hope this helps
3 0
3 years ago
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