Proton: Its electrical charge is +1, its mass is 1, it's found in the nucleus
Neutron: Its electrical charge is 0, its mass is 1, it's found in the nucleus
Electron: Its electrical charge is -1, its mass is negligible, it's found outside the nucleus
Explanation:
Atoms consist of three types of particles:
- Proton: the proton is found in the nucleus of the atom, and it has a positive electric charge, equal to
(expressed in units of fundamental charge, it has a charge of +1). Its mass is 
, while its mass expressed in atomic mass units is 1 a.m.u - Neutron: the neutron is also found in the nucleus of the atom, and it has no electric charge. Its mass is similar to the mass of the proton (slightly larger), and neutrons and protons are held together in the nucleus by the presence of the strong nuclear force
- Electron: the electron orbits around the nucleus, far away from it. It has negative electric charge, opposite to that of the proton (
, or -1 in units of fundamental charge). Its mass is much lower than that of the proton, approximately 1800 times smaller, so it can be considered as negligible.
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The person is at rest with respect to the car. So the best answer is:
c. the front seat of the car.
Answer:
63.78%
Explanation:
The equation that relates the angle of the polarization and the intensity of ligth transmitted is I=Io*cos²(x), where I is the intensity of the incident light, Io is the intensity of the transmitted light, and x is the angle of polarization. The fraction of incident light will be I/Io, so the answer in given by cos²(37) = 0.6378
Answer:
The initial volume of the system is 2.7 L
Explanation:
The change in internal energy is given by;
ΔU = Q - W
where;
Q is the heat absorb from the surrounding
W is the work done by the system
Given;
ΔU = -107.6 J
Q = 59 J
W = ?
W = Q- ΔU
W = 59J - (-107.6)
W = 166.6 J
Work done is given by;
W = PΔV
W = P(V₂ - V₁)
101.325 Joules = 1 L.atm
166.6 Joules = ?
= 1.644 L.atm
1.644 L.atm = 0.543 atm(57.7L - V₁)
57.7L - V₁ = (1.644 L.atm) / (0.543 atm)
57.7L - V₁ = 3.0 L
V₁ = 57.7L - 3.0 L
V₁ = 2.7 L
Therefore, the initial volume of the system is 2.7 L
