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Naddik [55]
3 years ago
11

Circle the path function(s) which are affected by a detailed path from one state to another: (A) Temperature (B) Boundary work (

C) Pressure (D) Heat (E) Volume
Physics
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

(B) Boundary work

(D) Heat

Explanation:

Boundary work and heat quantitatively describe the transition between equilibrium states of thermodynamic systems. They are not only a function of the initial and final states, but also of the successive intermediate states through which the system passes, this is, depend on the path taken to reach one state from another. Thus, are path functions.

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Which pair of triangles can be proven congruent by the hl theorem?
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The pairs of triangles that can be proven congruent by the hl theorem is the right angled triangle.

<h3>What is mearnt be the HL theorm?</h3>

The HL theorem is also known as the Hypothenus Leg theorem, it states that "the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent."

Learn more about the postulates of the HL theorem here:

brainly.com/question/25922842

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The simplest form of a substance
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Answer :

C) Atom

Actual answer should be element but depends on the way you interpret the question and the options given to answer it

Explanation :

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Hope it helps if it does let me know by thanking
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3 years ago
ABCD next 3 letters??????
jasenka [17]

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3 years ago
An alpha particle (the nucleus of a helium atom) consists of two protons and two neutrons, and has a mass of 6.64 * 10-27 kg. A
melamori03 [73]

Answer:

t = 4.21x10⁻⁷ s

Explanation:

The time (t) can be found using the angular velocity (ω):

\omega = \frac{\theta}{t}

<em>Where θ: is the angular displacement = π (since it moves halfway through a complete circle)</em>

We have:

t = \frac{\theta}{\omega} = \frac{\theta}{v/r}  

<u>Where</u>:      

<em>v: is the tangential speed </em>

<em>r: is the radius</em>

The radius can be found equaling the magnetic force with the centripetal force:

qvB = \frac{mv^{2}}{r} \rightarrow r = \frac{mv}{qB}

Where:

m: is the mass of the alpha particle = 6.64x10⁻²⁷ kg

q: is the charge of the alpha particle = 2*p (proton) = 2*1.6x10⁻¹⁹C

B: is the magnetic field = 0.155 T

Hence, the time is:

t = \frac{\theta*r}{v} = \frac{\theta}{v}*\frac{mv}{qB} = \frac{\theta m}{qB} = \frac{\pi * 6.64 \cdot 10^{-27} kg}{2*1.6 \cdot 10^{-19} C*0.155 T} = 4.21 \cdot 10^{-7} s

Therefore, the time that takes for an alpha particle to move halfway through a complete circle is 4.21x10⁻⁷ s.

I hope it helps you!    

4 0
3 years ago
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